Sometimes, while working with data, we may have a problem in which we require to find the matching records between two lists that we receive. This is a very common problem and records usually occur as a tuple. Let’s discuss certain ways in which this problem can be solved.

**Method #1 : Using list comprehension**

List comprehension can opt as method to perform this task in one line rather than running a loop to find the common element. In this, we just iterate for single list and check if any element occurs in other one.

`# Python3 code to demonstrate working of` `# Intersection in Tuple Records Data` `# Using list comprehension` ` ` `# Initializing lists` `test_list1 ` `=` `[(` `'gfg'` `, ` `1` `), (` `'is'` `, ` `2` `), (` `'best'` `, ` `3` `)]` `test_list2 ` `=` `[(` `'i'` `, ` `3` `), (` `'love'` `, ` `4` `), (` `'gfg'` `, ` `1` `)]` ` ` `# printing original lists` `print` `(` `"The original list 1 is : "` `+` `str` `(test_list1))` `print` `(` `"The original list 2 is : "` `+` `str` `(test_list2))` ` ` `# Intersection in Tuple Records Data` `# Using list comprehension` `res ` `=` `[ele1 ` `for` `ele1 ` `in` `test_list1 ` ` ` `for` `ele2 ` `in` `test_list2 ` `if` `ele1 ` `=` `=` `ele2]` ` ` `# printing result` `print` `(` `"The Intersection of data records is : "` `+` `str` `(res))` |

**Output :**

The original list 1 is : [('gfg', 1), ('is', 2), ('best', 3)] The original list 2 is : [('i', 3), ('love', 4), ('gfg', 1)] The Intersection of data records is : [('gfg', 1)]

**Method #2 : Using set.intersection()**

This task can also be performed in smaller way using the generic set intersection. In this, we first convert the list of records to a set and then perform its intersection using

`intersection()`

.`# Python3 code to demonstrate working of` `# Intersection in Tuple Records Data` `# Using set.intersection()` ` ` `# Initializing lists` `test_list1 ` `=` `[(` `'gfg'` `, ` `1` `), (` `'is'` `, ` `2` `), (` `'best'` `, ` `3` `)]` `test_list2 ` `=` `[(` `'i'` `, ` `3` `), (` `'love'` `, ` `4` `), (` `'gfg'` `, ` `1` `)]` ` ` `# printing original lists` `print` `(` `"The original list 1 is : "` `+` `str` `(test_list1))` `print` `(` `"The original list 2 is : "` `+` `str` `(test_list2))` ` ` `# Intersection in Tuple Records Data` `# set.intersection()` `res ` `=` `list` `(` `set` `(test_list1).intersection(` `set` `(test_list2)))` ` ` `# printing result` `print` `(` `"The Intersection of data records is : "` `+` `str` `(res))` |

**Output :**

The original list 1 is : [('gfg', 1), ('is', 2), ('best', 3)] The original list 2 is : [('i', 3), ('love', 4), ('gfg', 1)] The Intersection of data records is : [('gfg', 1)]

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