# Python | Intersection in Tuple Records Data

• Last Updated : 29 Oct, 2019

Sometimes, while working with data, we may have a problem in which we require to find the matching records between two lists that we receive. This is a very common problem and records usually occur as a tuple. Let’s discuss certain ways in which this problem can be solved.

Method #1 : Using list comprehension
List comprehension can opt as method to perform this task in one line rather than running a loop to find the common element. In this, we just iterate for single list and check if any element occurs in other one.

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 `# Python3 code to demonstrate working of``# Intersection in Tuple Records Data``# Using list comprehension`` ` `# Initializing lists``test_list1 ``=` `[(``'gfg'``, ``1``), (``'is'``, ``2``), (``'best'``, ``3``)]``test_list2 ``=` `[(``'i'``, ``3``), (``'love'``, ``4``), (``'gfg'``, ``1``)]`` ` `# printing original lists``print``(``"The original list 1 is : "` `+` `str``(test_list1))``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Intersection in Tuple Records Data``# Using list comprehension``res ``=` `[ele1 ``for` `ele1 ``in` `test_list1 ``       ``for` `ele2 ``in` `test_list2 ``if` `ele1 ``=``=` `ele2]`` ` `# printing result``print``(``"The Intersection of data records is : "` `+` `str``(res))`
Output :

```The original list 1 is : [('gfg', 1), ('is', 2), ('best', 3)]
The original list 2 is : [('i', 3), ('love', 4), ('gfg', 1)]
The Intersection of data records is : [('gfg', 1)]
```

Method #2 : Using `set.intersection()`
This task can also be performed in smaller way using the generic set intersection. In this, we first convert the list of records to a set and then perform its intersection using `intersection()`.

 `# Python3 code to demonstrate working of``# Intersection in Tuple Records Data``# Using set.intersection()`` ` `# Initializing lists``test_list1 ``=` `[(``'gfg'``, ``1``), (``'is'``, ``2``), (``'best'``, ``3``)]``test_list2 ``=` `[(``'i'``, ``3``), (``'love'``, ``4``), (``'gfg'``, ``1``)]`` ` `# printing original lists``print``(``"The original list 1 is : "` `+` `str``(test_list1))``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Intersection in Tuple Records Data``# set.intersection()``res ``=` `list``(``set``(test_list1).intersection(``set``(test_list2)))`` ` `# printing result``print``(``"The Intersection of data records is : "` `+` `str``(res))`
Output :
```The original list 1 is : [('gfg', 1), ('is', 2), ('best', 3)]
The original list 2 is : [('i', 3), ('love', 4), ('gfg', 1)]
The Intersection of data records is : [('gfg', 1)]
```

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