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# Python – Inner Nested Value List Mean in Dictionary

• Last Updated : 04 Feb, 2023

Sometimes, while working with Python Dictionaries, we can have a problem in which we need to extract the mean of nested value lists in dictionary. This problem can have application in many domains including web development and competitive programming. Lets discuss certain ways in which this task can be performed.

Method #1 : Using mean() + loop The combination of above functions provide the brute way to solve this problem. In this, we perform the task of finding mean using inbuilt mean() library and iterate for nesting using loop.

## Python3

 `# Python3 code to demonstrate working of``# Inner Nested Value List Mean in Dictionary``# Using mean() + loop``from` `statistics ``import` `mean` `# initializing dictionary``test_dict ``=` `{``'Gfg'` `: {``'a'` `: [``1``, ``5``, ``6``, ``7``], ``'b'` `: [``6``, ``7``, ``8``, ``9``]}, ``'is'` `: {``'best'` `:[``2``, ``8``, ``9``, ``0``]}}` `# printing original dictionary``print``("The original dictionary : " ``+` `str``(test_dict))` `# Inner Nested Value List Mean in Dictionary``# Using mean() + loop``for` `sub ``in` `test_dict.values():``    ``for` `key ``in` `sub:``        ``sub[key] ``=` `mean(sub[key])` `# printing result``print``("The modified dictionary : " ``+` `str``(test_dict))`

Output :

The original dictionary : {‘Gfg’: {‘a’: [1, 5, 6, 7], ‘b’: [6, 7, 8, 9]}, ‘is’: {‘best’: [2, 8, 9, 0]}} The modified dictionary : {‘Gfg’: {‘a’: 4.75, ‘b’: 7.5}, ‘is’: {‘best’: 4.75}}

Time Complexity: O(N), where N is the total number of elements in the dictionary, as we are iterating through the values of the dictionary and for each value, we are computing the mean of its corresponding list, which takes O(n) time, where n is the length of the list.
Auxiliary Space: O(1), as we are using the mean function from the statistics library, which uses a constant amount of space to store temporary variables.

Method #2 : Using dictionary comprehension + mean() This is yet another way to solve this problem. In this, we perform similar task as above method. But difference is that in compact way and as one-liner.

## Python3

 `# Python3 code to demonstrate working of``# Inner Nested Value List Mean in Dictionary``# Using dictionary comprehension + mean()``from` `statistics ``import` `mean` `# initializing dictionary``test_dict ``=` `{``'Gfg'` `: {``'a'` `: [``1``, ``5``, ``6``, ``7``], ``'b'` `: [``6``, ``7``, ``8``, ``9``]}, ``'is'` `: {``'best'` `:[``2``, ``8``, ``9``, ``0``]}}` `# printing original dictionary``print``("The original dictionary : " ``+` `str``(test_dict))` `# Inner Nested Value List Mean in Dictionary``# Using dictionary comprehension + mean()``res ``=` `{idx: {key: mean(idx) ``for` `key, idx ``in` `j.items()} ``for` `idx, j ``in` `test_dict.items()}` `# printing result``print``("The modified dictionary : " ``+` `str``(res))`

Output :

The original dictionary : {‘Gfg’: {‘a’: [1, 5, 6, 7], ‘b’: [6, 7, 8, 9]}, ‘is’: {‘best’: [2, 8, 9, 0]}} The modified dictionary : {‘Gfg’: {‘a’: 4.75, ‘b’: 7.5}, ‘is’: {‘best’: 4.75}}

Time Complexity: O(n), where n is the total number of elements in the dictionary. The dictionary comprehension used here requires a single pass through the dictionary to calculate the mean of each nested list.
Auxiliary Space: O(m), where m is the number of elements in the result dictionary. The result dictionary takes O(m) space in the memory as it stores the mean of each nested list.

Method #3 : Using sum()+len()+for loop

## Python3

 `# Python3 code to demonstrate working of``# Inner Nested Value List Mean in Dictionary` `# initializing dictionary``test_dict ``=` `{``'Gfg'` `: {``'a'` `: [``1``, ``5``, ``6``, ``7``], ``'b'` `: [``6``, ``7``, ``8``, ``9``]}, ``'is'` `: {``'best'` `:[``2``, ``8``, ``9``, ``0``]}}` `# printing original dictionary``print``(``"The original dictionary : "` `+` `str``(test_dict))` `# Inner Nested Value List Mean in Dictionary` `for` `sub ``in` `test_dict.values():``    ``for` `key ``in` `sub:``        ``sub[key] ``=` `sum``(sub[key])``/``len``(sub[key])` `# printing result``print``(``"The modified dictionary : "` `+` `str``(test_dict))`

Output

```The original dictionary : {'Gfg': {'a': [1, 5, 6, 7], 'b': [6, 7, 8, 9]}, 'is': {'best': [2, 8, 9, 0]}}
The modified dictionary : {'Gfg': {'a': 4.75, 'b': 7.5}, 'is': {'best': 4.75}}```

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