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Python | Incremental Records Product
• Last Updated : 10 Jan, 2020

Sometimes, while working with data, we can have a problem in which we need to find accumulative product of each index in tuples. This problem can have application in web development and competitive programming domain. Let’s discuss certain way in which this problem can be solved.

Method : Using `accumulate()` + loop + `lambda + map() + tuple() + zip()`
The combination of above functions can be used to solve this task. In this, we pair the elements using zip(), the then we perform the product of them and we extend this to all elements using map(). The taking forward of product is done by using accumulate. The binding of all logic is done by lambda function.

 `# Python3 code to demonstrate working of``# Incremental Records Product``# Using accumulate() + loop + lambda + map() + tuple() + zip()``from` `itertools ``import` `accumulate`` ` `def` `prod(val) :     ``    ``res ``=` `1`         `    ``for` `ele ``in` `val:         ``        ``res ``*``=` `ele         ``    ``return` `res``     ` `# initialize list``test_list ``=` `[(``3``, ``4``, ``5``), (``4``, ``5``, ``7``), (``1``, ``4``, ``10``)]`` ` `# printing original list ``print``(``"The original list : "` `+` `str``(test_list))`` ` `# Incremental Records Product``# Using accumulate() + loop + lambda + map() + tuple() + zip()``res ``=` `list``(accumulate(test_list, ``lambda` `i, j: ``tuple``(``map``(prod, ``zip``(i, j)))))`` ` `# printing result``print``(``"Accumulative index product of tuple list : "` `+` `str``(res))`
Output :
```The original list : [(3, 4, 5), (4, 5, 7), (1, 4, 10)]
Accumulative index product of tuple list : [(3, 4, 5), (12, 20, 35), (12, 80, 350)]
```

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