# Python – How to Sort a Dictionary by Kth Index Value

While working with Python, one might come to a problem in which one needs to perform a sort on dictionary based on Kth index of value list. This can be typically in case of scoring or web development. Let’s discuss a method by which this task can be performed.

Input : test_dict = {‘gfg’ : [5, 6, 7], ‘is’ : [1, 4, 7], ‘best’ : [8, 3, 1]}, K = 2
Output : [(‘best’, [8, 3, 1]), (‘gfg’, [5, 6, 7]), (‘is’, [1, 4, 7])]

Input : test_dict = {‘gfg’ : [5, 6, 7], ‘is’ : [1, 4, 7], ‘best’ : [8, 3, 1]}, K = 0
Output : [(‘is’, [1, 4, 7]), (‘gfg’, [5, 6, 7]), (‘best’, [8, 3, 1])]

Method : Using `sorted()` + lambda
The combination of above functions can be used to solve this problem. In this, we perform sort using sorted() and lambda function is used to drive Kth index logic.

 `# Python3 code to demonstrate working of  ` `# Sort Dictionary by Kth Index Value ` `# Using sorted() + lambda ` ` `  `# initializing dictionary ` `test_dict ``=` `{``'gfg'` `: [``5``, ``6``, ``7``], ` `             ``'is'` `: [``1``, ``4``, ``7``], ` `             ``'best'` `: [``8``, ``3``, ``1``]} ` ` `  `# printing original dictionary ` `print``(``"The original dictionary is : "` `+` `str``(test_dict)) ` ` `  `# initializing K ` `K ``=` `1` ` `  `# Sort Dictionary by Kth Index Value ` `# Using sorted() + lambda ` `res ``=` `sorted``(test_dict.items(), key ``=` `lambda` `key: key[``1``][K]) ` ` `  `# printing result  ` `print``(``"The sorted dictionary : "` `+` `str``(res))  `

Output :

```The original dictionary is : {'gfg': [5, 6, 7], 'is': [1, 4, 7], 'best': [8, 3, 1]}
The sorted dictionary : [('best', [8, 3, 1]), ('is', [1, 4, 7]), ('gfg', [5, 6, 7])]
```

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