# Python | How to get unique elements in nested tuple

• Last Updated : 21 Aug, 2022

Sometimes, while working with tuples, we can have a problem in which we have nested tuples and we need to extract elements that occur singly, i.e are elementary. This kind of problem can have applications in many domains. Let’s discuss certain ways in which this problem can be solved.

### Method #1: Using nested loop + set()

The above 2 functionalities can be used to solve this particular problem. In this, we iterate each nested tuple and add to the set if the element has occurred for the first time and check for each element before adding.

## Python3

 `# Python3 code to demonstrate working of``# Unique elements in nested tuple``# Using nested loop + set()` `# initialize list``test_list ``=` `[(``3``, ``4``, ``5``), (``4``, ``5``, ``7``), (``1``, ``4``)]` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))` `# Unique elements in nested tuple``# Using nested loop + set()``res ``=` `[]``temp ``=` `set``()``for` `inner ``in` `test_list:``        ``for` `ele ``in` `inner:``            ``if` `not` `ele ``in` `temp:``                ``temp.add(ele)``                ``res.append(ele)` `# printing result``print``(``"Unique elements in nested tuples are : "` `+` `str``(res))`

Output

```The original list : [(3, 4, 5), (4, 5, 7), (1, 4)]
Unique elements in nested tuples are : [3, 4, 5, 7, 1]```

### Method #2 : Using set() + from_iterable()

The combo of the above functionalities can be used to solve this. This is done is 2 steps, first, we flatten the nested list and then find distinct using set() method.

## Python3

 `# Python3 code to demonstrate working of``# Unique elements in nested tuple``# Using from_iterable() + set()``from` `itertools ``import` `chain` `# initialize list``test_list ``=` `[(``3``, ``4``, ``5``), (``4``, ``5``, ``7``), (``1``, ``4``)]` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))` `# Unique elements in nested tuple``# Using from_iterable() + set()``res ``=` `list``(``set``(chain.from_iterable(test_list)))` `# printing result``print``(``"Unique elements in nested tuples are : "` `+` `str``(res))`

Output

```The original list : [(3, 4, 5), (4, 5, 7), (1, 4)]
Unique elements in nested tuples are : [1, 3, 4, 5, 7]```

## Python3

 `# Python3 code to demonstrate working of``# Unique elements in nested tuple` `# initialize list``test_list ``=` `[(``3``, ``4``, ``5``), (``4``, ``5``, ``7``), (``1``, ``4``)]` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))` `# Unique elements in nested tuple``x``=``[]``for` `i ``in` `test_list:``    ``i``=``list``(i)``    ``x.extend(i)``res``=``list``(``set``(x))``# printing result``print``(``"Unique elements in nested tuples are : "` `+` `str``(res))`

Output

```The original list : [(3, 4, 5), (4, 5, 7), (1, 4)]
Unique elements in nested tuples are : [1, 3, 4, 5, 7]```

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