Python | How to get unique elements in nested tuple

• Last Updated : 21 Nov, 2019

Sometimes, while working with tuples, we can have a problem in which we have nested tuples and we need to extract elements that occur singly, i.e are elementary. This kind of problem can have applications in many domains. Let’s discuss certain ways in which this problem can be solved.

Method #1 : Using nested loop + set()
The above 2 functionalities can be used to solve this particular problem. In this, we iterate each nested tuple and add to set if element has occurred for first time and check for each element before adding.

 # Python3 code to demonstrate working of# Unique elements in nested tuple# Using nested loop + set()  # initialize listtest_list = [(3, 4, 5), (4, 5, 7), (1, 4)]  # printing original list print("The original list : " + str(test_list))  # Unique elements in nested tuple# Using nested loop + set()res = []temp = set()for inner in test_list:        for ele in inner:            if not ele in temp:                temp.add(ele)                res.append(ele)  # printing resultprint("Unique elements in nested tuples are : " + str(res))
Output :
The original list : [(3, 4, 5), (4, 5, 7), (1, 4)]
Unique elements in nested tuples are : [3, 4, 5, 7, 1]

Method #2 : Using set() + from_iterable()
The combo of above functionalities can be used to solve this. This is done is 2 steps, first, we flatten the nested list and then find distincts using set().

 # Python3 code to demonstrate working of# Unique elements in nested tuple# Using from_iterable() + set()from itertools import chain  # initialize listtest_list = [(3, 4, 5), (4, 5, 7), (1, 4)]  # printing original list print("The original list : " + str(test_list))  # Unique elements in nested tuple# Using from_iterable() + set()res = list(set(chain.from_iterable(test_list)))  # printing resultprint("Unique elements in nested tuples are : " + str(res))
Output :
The original list : [(3, 4, 5), (4, 5, 7), (1, 4)]
Unique elements in nested tuples are : [1, 3, 4, 5, 7]

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