# Python – Group elements from Dual List Matrix

• Last Updated : 06 Mar, 2020

Sometimes, while working with Python list, we can have a problem in which we need to group the elements in list with the first element of Matrix and perform the Grouping in form of dictionary. This can have advantage in many domains. Lets discuss certain ways in which this task can be performed.

Method #1 : Using loop + list comprehension
The combination of above methods can be used in performing this task. In this, we iterate through the dual element row and compute the dictionary with mapping of elements from list and 2nd column of dual row matrix.

 `# Python3 code to demonstrate ``# Group elements from Dual List Matrix``# using loop + list comprehension`` ` `# Initializing lists``test_list1 ``=` `[``'Gfg'``, ``'is'``, ``'best'``]``test_list2 ``=` `[[``'Gfg'``, ``1``], [``'is'``, ``2``], [``'best'``, ``1``], [``'Gfg'``, ``4``], [``'is'``, ``8``], [``'Gfg'``, ``7``]]`` ` `# printing original lists``print``(``"The original list 1 is : "` `+` `str``(test_list1))``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Group elements from Dual List Matrix``# using loop + list comprehension``res ``=` `{key: [] ``for` `key ``in` `test_list1}``for` `key ``in` `res:``    ``res[key] ``=` `[sub[``1``] ``for` `sub ``in` `test_list2 ``if` `key ``=``=` `sub[``0``]]``             ` `# printing result ``print` `(``"The dictionary after grouping : "` `+` `str``(res))`

Output :

The original list 1 is : [‘Gfg’, ‘is’, ‘best’]
The original list 2 is : [[‘Gfg’, 1], [‘is’, 2], [‘best’, 1], [‘Gfg’, 4], [‘is’, 8], [‘Gfg’, 7]]
The dictionary after grouping : {‘is’: [2, 8], ‘Gfg’: [1, 4, 7], ‘best’: }

Method #2 : Using dictionary comprehension
This is yet another way in which this task can be performed. In this, we compile the logic performed above into one single dictionary comprehension for better readability.

 `# Python3 code to demonstrate ``# Group elements from Dual List Matrix``# using dictionary comprehension`` ` `# Initializing lists``test_list1 ``=` `[``'Gfg'``, ``'is'``, ``'best'``]``test_list2 ``=` `[[``'Gfg'``, ``1``], [``'is'``, ``2``], [``'best'``, ``1``], [``'Gfg'``, ``4``], [``'is'``, ``8``], [``'Gfg'``, ``7``]]`` ` `# printing original lists``print``(``"The original list 1 is : "` `+` `str``(test_list1))``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Group elements from Dual List Matrix``# using dictionary comprehension``res ``=` `{key: [sub[``1``] ``for` `sub ``in` `test_list2 ``if` `key ``=``=` `sub[``0``]] ``for` `key ``in` `test_list1}``             ` `# printing result ``print` `(``"The dictionary after grouping : "` `+` `str``(res))`

Output :

The original list 1 is : [‘Gfg’, ‘is’, ‘best’]
The original list 2 is : [[‘Gfg’, 1], [‘is’, 2], [‘best’, 1], [‘Gfg’, 4], [‘is’, 8], [‘Gfg’, 7]]
The dictionary after grouping : {‘is’: [2, 8], ‘Gfg’: [1, 4, 7], ‘best’: }

My Personal Notes arrow_drop_up