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Python | Get Top N elements from Records
• Last Updated : 29 Oct, 2019

Sometimes, while working with data, we can have a problem in which we have records and we require to find the highest N scores from it. This kind of application is popular in web development domain. Let’s discuss certain ways in which this problem can be solved.

Method #1 : Using `sorted()` + lambda
The combination of above functionality can be used to perform this particular task. In this, we just employ sorted function with reverse flag true, and print the top N elements using list slicing.

 `# Python3 code to demonstrate working of``# Get Top N elements from Records``# Using sorted() + lambda`` ` `# Initializing list ``test_list ``=` `[(``'Manjeet'``, ``10``), (``'Akshat'``, ``4``), (``'Akash'``, ``2``), (``'Nikhil'``, ``8``)]`` ` `# Initializing N ``N ``=` `2`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# Get Top N elements from Records``# Using sorted() + lambda``res ``=` `sorted``(test_list, key ``=` `lambda` `x: x[``1``], reverse ``=` `True``)[:N]`` ` `# printing result``print``(``"The top N records are : "` `+` `str``(res))`
Output :
```The original list is : [('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)]
The top N records are : [('Manjeet', 10), ('Nikhil', 8)]
```

`Method #2 : Using sorted() + itemgetter()`
The combination of above functions can also be used to perform this particular task. In this, the task performed by lambda function is performed by `itemgetter()` is used to get the index in tuple which has to be included in calculations.

 `# Python3 code to demonstrate working of``# Get Top N elements from Records``# Using sorted() + itemgetter()``from` `operator ``import` `itemgetter`` ` `# Initializing list ``test_list ``=` `[(``'Manjeet'``, ``10``), (``'Akshat'``, ``4``), (``'Akash'``, ``2``), (``'Nikhil'``, ``8``)]`` ` `# Initializing N ``N ``=` `2`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# Get Top N elements from Records``# Using sorted() + itemgetter()``res ``=` `sorted``(test_list, key ``=` `itemgetter(``1``), reverse ``=` `True``)[:N]`` ` `# printing result``print``(``"The top N records are : "` `+` `str``(res))`
Output :
```The original list is : [('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)]
The top N records are : [('Manjeet', 10), ('Nikhil', 8)]
```

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