# Python | Get the numeric prefix of given string

• Last Updated : 04 Feb, 2023

Given a string. the task is to print numeric prefix in string (if it is present in string). Given below are few methods to solve the task.

Method #1: Using Naive Method

## Python3

 `# Python code to demonstrate``# to get numeric prefix in string``# if present` `# initialising string``ini_string ``=` `"``123abcjw``"``ini_string2 ``=` `"abceddfgh"` `# printing string and its length``print` `("initial string : ", ini_string, ini_string2)` `# code to find numeric prefix in string``res1 ``=` `'``'.join(c for c in ini_string if c in '``0123456789``')``res2 ``=` `'``'.join(c for c in ini_string2 if c in '``0123456789``')`  `# printing resultant string``print` `("first string result: ", ``str``(res1))``print` `("second string result: ", ``str``(res2))`

Output:

```initial string :  123abcjw abceddfgh
first string result:  123
second string result:```

Time Complexity: O(n + m), where n + m are the length of given strings
Auxiliary Space: O(n + m)

Method #2: Using takewhile

## Python3

 `# Python code to demonstrate``# to get numeric prefix in string``# if present``from` `itertools ``import` `takewhile` `# initialising string``ini_string ``=` `"``123abcjw``"``ini_string2 ``=` `"abceddfgh"` `# printing string and its length``print` `("initial string : ", ini_string, ini_string2)` `# code to find numeric prefix in string``res1 ``=` `''.join(takewhile(``str``.isdigit, ini_string))``res2 ``=` `''.join(takewhile(``str``.isdigit, ini_string2))` `# printing resultant string``print` `("first string result: ", res1)``print` `("second string result: ", res2)`

Output:

```initial string :  123abcjw abceddfgh
first string result:  123
second string result:```

Time complexity: O(n), where n is the length of the string, since the code uses a for loop to iterate through the string and calls the built-in method str.isdigit() for each character in the string.
Auxiliary space: O(m), where m is the length of the numeric prefix in the string.

Method #3: Using re.sub

## Python3

 `# Python code to demonstrate``# to get numeric prefix in string``# if present``import` `re` `# initialising string``ini_string ``=` `"``123abcjw``"``ini_string2 ``=` `"abceddfgh"` `# printing string and its length``print` `("initial string : ", ini_string, ini_string2)` `# code to find numeric prefix in string``res1 ``=` `re.sub(``'\D.*'``, '', ini_string)``res2 ``=` `re.sub(``'\D.*'``, '', ini_string2)`  `# printing resultant string``print` `("first string result: ", ``str``(res1))``print` `("second string result: ", ``str``(res2))`

Output:

```initial string :  123abcjw abceddfgh
first string result:  123
second string result:```

Time Complexity: O(n), where n is the length of the string.
Auxiliary Space: O(1).

Using Method #4: Using re.findall

## Python3

 `# Python code to demonstrate``# to get numeric prefix in string``# if present``import` `re` `# initialising string``ini_string ``=` `"``123abcjw``"``ini_string2 ``=` `"abceddfgh"` `# printing string and its length``print` `("initial string : ", ini_string, ini_string2)` `# code to find numeric prefix in string``res1 ``=` `'``'.join(re.findall('``\d``+``', ini_string))``res2 ``=` `'``'.join(re.findall('``\d``+``', ini_string2))` `# printing resultant string``print` `("first string result: ", ``str``(res1))``print` `("second string result: ", ``str``(res2))`

Output:

```initial string :  123abcjw abceddfgh
first string result:  123
second string result:```

Method #5: Using isalpha() method

## Python3

 `# Python code to demonstrate``# to get numeric prefix in string``# if present``def` `fun(s):``    ``x``=``""``    ``for` `i ``in` `s:``        ``if` `i.isalpha():``            ``break``        ``else``:``            ``x``+``=``i``    ``return` `x``# initialising string``ini_string ``=` `"123abcjw"``ini_string2 ``=` `"abceddfgh"` `# printing string and its length``print` `(``"initial string : "``, ini_string, ini_string2)``# code to find numeric prefix in string``res1 ``=` `fun(ini_string)``res2 ``=` `fun(ini_string2)``# printing resultant string``print` `(``"first string result: "``, res1)``print` `(``"second string result: "``, res2)`

Output

```initial string :  123abcjw abceddfgh
first string result:  123
second string result:  ```

Time Complexity : O(N)
Auxiliary Space : O(N)

Method #6: Using re.search()

In the above code, we are using the search function from the re module to find the longest prefix of numeric characters in the input string. The regular expression r’^\d+’ matches one or more digits at the beginning of the string (the ^ symbol represents the start of the string).

If a match is found, the search function returns a Match object representing the match. We can use the group method of this object to extract the matched string. If no match is found, search returns None, and we return an empty string instead.

Finally, we use the print function to output the resulting prefix for each example input string.

## Python

 `import` `re` `def` `get_numeric_prefix(s):``    ``"""``    ``Extracts the numeric prefix from a string.``    ``"""``    ``# Use a regular expression to match the longest prefix of numeric characters``    ``match ``=` `re.search(r``'^\d+'``, s)``    ``if` `match:``        ``# Return the matched prefix``        ``return` `match.group()``    ``else``:``        ``# If no match was found, return an empty string``        ``return` `""` `# Example usage``print``(get_numeric_prefix(``"123abcjw"``))``print``(get_numeric_prefix(``"abceddfgh"``))``print``(get_numeric_prefix(``"123abcjw12"``))``#This code is contributed by Edula Vinay Kumar Reddy`

Output

```123

123```

Time Complexity O(n), where n is the length of the input string.
Auxiliary Space: O(n).

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