# Python | Get the Index of first element greater than K

• Last Updated : 30 Sep, 2019

Python list operations are always desired to have shorthands as they are used in many places in development. Hence having knowledge of them always remains quite useful.
Let’s deals with finding one such utility of having index of first element greater than K by one-liner. There are various ways in which this can be achieved.

Method #1 : Using `next() + enumerate()`
Using `next()` returns the iterator to the element that has been using the `enumerate()`. We simply put the condition for enumerate and `next()` picks appropriate element index.

 `# Python3 code to demonstrate ``# to find index of first element just ``# greater than K ``# using enumerate() + next()`` ` `# initializing list``test_list ``=` `[``0.4``, ``0.5``, ``11.2``, ``8.4``, ``10.4``]`` ` `# printing original list``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# using enumerate() + next() to find index of``# first element just greater than 0.6 ``res ``=` `next``(x ``for` `x, val ``in` `enumerate``(test_list)``                                  ``if` `val > ``0.6``)`` ` `# printing result``print` `(``"The index of element just greater than 0.6 : "``                                           ``+` `str``(res))`

Output:

```The original list is : [0.4, 0.5, 11.2, 8.4, 10.4]
The index of element just greater than 0.6 : 2
```

Method #2 : Using `filter()` + lambda
Using filter along with lambda can also help us to achieve this particular task, subscript index value 0 is used to specify that first element greater than value has to be taken.

 `# Python3 code to demonstrate ``# to find index of first element just ``# greater than K ``# using filter() + lambda`` ` `# initializing list``test_list ``=` `[``0.4``, ``0.5``, ``11.2``, ``8.4``, ``10.4``]`` ` `# printing original list``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# using filter() + lambda``# to find index of first element just ``# greater than 0.6 ``res ``=` `list``(``filter``(``lambda` `i: i > ``0.6``, test_list))[``0``]`` ` `# printing result``print` `(``"The index of element just greater than 0.6 : "``                          ``+` `str``(test_list.index(res)))`

Output:

```The original list is : [0.4, 0.5, 11.2, 8.4, 10.4]
The index of element just greater than 0.6 : 2
```

Method #3 : Using `map() + index()`
`map()` along with the `index()` can also return the desired element index and has the similar internal working as method 1 as discussed above.

 `# Python3 code to demonstrate ``# to find index of first element just ``# greater than K ``# using map() + index()`` ` `# initializing list``test_list ``=` `[``0.4``, ``0.5``, ``11.2``, ``8.4``, ``10.4``]`` ` `# printing original list``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# using map() + index()``# to find index of first element just ``# greater than 0.6 ``res ``=` `list``(``map``(``lambda` `i: i> ``0.6``, test_list)).index(``True``)`` ` `# printing result``print` `(``"The index of element just greater than 0.6 : "``                                           ``+` `str``(res))`

Output:

```The original list is : [0.4, 0.5, 11.2, 8.4, 10.4]
The index of element just greater than 0.6 : 2
```

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