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Python | Get first N key:value pairs in given dictionary

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  • Last Updated : 02 Aug, 2019

Given a dictionary, the task is to get N key:value pairs from given dictionary. This type of problem can be useful while some cases, like fetching first N values in web development.

Note that the given dictionary is unordered, the first N pairs will not be same here all the time. In case, you need to maintain order in your problem, you can use ordered dictionary.

Code #1: Using itertools.islice() method




# Python program to get N key:value pairs in given dictionary
# using itertools.islice() method
  
import itertools 
    
# Initialize dictionary
test_dict = {'Geeks' : 1, 'For':2'is' : 3, 'best' : 4, 'for' : 5, 'CS' : 6
    
# printing original dictionary 
print("The original dictionary : " +  str(test_dict)) 
    
# Initialize limit 
N = 3
    
# Using islice() + items() 
# Get first N items in dictionary 
out = dict(itertools.islice(test_dict.items(), N)) 
        
# printing result  
print("Dictionary limited by K is : " + str(out)) 

Output:

The original dictionary : {‘for’: 5, ‘best’: 4, ‘CS’: 6, ‘is’: 3, ‘Geeks’: 1, ‘For’: 2}
Dictionary limited by K is : {‘for’: 5, ‘best’: 4, ‘CS’: 6}

 

Code #2: Using slicing on dictionary item list




# Python program to get N key:value pairs in given dictionary
# using list slicing
    
# Initialize dictionary
test_dict = {'Geeks' : 1, 'For':2'is' : 3, 'best' : 4, 'for' : 5, 'CS' : 6
    
# printing original dictionary 
print("The original dictionary : " +  str(test_dict)) 
    
# Initialize limit 
N = 3
    
# Using items() + list slicing 
# Get first K items in dictionary 
out = dict(list(test_dict.items())[0: N]) 
        
# printing result  
print("Dictionary limited by K is : " + str(out)) 

Output:

The original dictionary : {‘best’: 3, ‘gfg’: 1, ‘is’: 2, ‘CS’: 5, ‘for’: 4}
Dictionary limited by K is : {‘best’: 3, ‘gfg’: 1, ‘is’: 2}


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