Python | Get first N key:value pairs in given dictionary
Given a dictionary, the task is to get N key:value pairs from given dictionary. This type of problem can be useful while some cases, like fetching first N values in web development.
Note that the given dictionary is unordered, the first N pairs will not be same here all the time. In case, you need to maintain order in your problem, you can use ordered dictionary.
Code #1: Using itertools.islice() method
# Python program to get N key:value pairs in given dictionary# using itertools.islice() method import itertools # Initialize dictionarytest_dict = {'Geeks' : 1, 'For':2, 'is' : 3, 'best' : 4, 'for' : 5, 'CS' : 6} # printing original dictionary print("The original dictionary : " + str(test_dict)) # Initialize limit N = 3 # Using islice() + items() # Get first N items in dictionary out = dict(itertools.islice(test_dict.items(), N)) # printing result print("Dictionary limited by K is : " + str(out)) |
Output:
The original dictionary : {‘for’: 5, ‘best’: 4, ‘CS’: 6, ‘is’: 3, ‘Geeks’: 1, ‘For’: 2}
Dictionary limited by K is : {‘for’: 5, ‘best’: 4, ‘CS’: 6}
Code #2: Using slicing on dictionary item list
# Python program to get N key:value pairs in given dictionary# using list slicing # Initialize dictionarytest_dict = {'Geeks' : 1, 'For':2, 'is' : 3, 'best' : 4, 'for' : 5, 'CS' : 6} # printing original dictionary print("The original dictionary : " + str(test_dict)) # Initialize limit N = 3 # Using items() + list slicing # Get first K items in dictionary out = dict(list(test_dict.items())[0: N]) # printing result print("Dictionary limited by K is : " + str(out)) |
Output:
The original dictionary : {‘best’: 3, ‘gfg’: 1, ‘is’: 2, ‘CS’: 5, ‘for’: 4}
Dictionary limited by K is : {‘best’: 3, ‘gfg’: 1, ‘is’: 2}
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