# Python | Flatten given list of dictionaries

Given a list of the dictionaries, the task is to convert it into single dictionary i.e flattening a list of dictionaries.

Given below are a few methods to solve the given task.

Method #1: Using Naive Method

 `# Python code to demonstrate ` `# to flatten list of dictionaries ` ` `  `# Initialising dictionary ` `ini_dict ``=` `[{``'a'``:``1``}, {``'b'``:``2``}, {``'c'``:``3``}] ` ` `  `# printing initial dictionary ` `print` `(``"initial dictionary"``, ``str``(ini_dict)) ` ` `  `# code to flatten lit of dictionary ` `res ``=` `{} ` `for` `d ``in` `ini_dict: ` `    ``res.update(d) ` `     `  `# printing result ` `print` `(``"result"``, ``str``(res)) `

Output:

```initial dictionary [{'a': 1}, {'b': 2}, {'c': 3}]
result {'b': 2, 'a': 1, 'c': 3}
```

Method #2: Using dict comprehension

 `# Python code to demonstrate ` `# to flatten list of dictionaries ` ` `  `# Initialising dictionary ` `ini_dict ``=` `[{``'a'``:``1``}, {``'b'``:``2``}, {``'c'``:``3``}] ` ` `  `# printing initial dictionary ` `print` `(``"initial dictionary"``, ``str``(ini_dict)) ` ` `  `# code to flatten lit of dictionary ` `res ``=` `{k: v ``for` `d ``in` `ini_dict ``for` `k, v ``in` `d.items()} ` `     `  `# printing result ` `print` `(``"result"``, ``str``(res)) `

Output:

```initial dictionary [{'a': 1}, {'b': 2}, {'c': 3}]
result {'a': 1, 'c': 3, 'b': 2}
```

Method #3: Using reduce

 `# Python code to demonstrate ` `# to flatten list of dictionaries ` `from` `functools ``import` `reduce`  ` `  `# Initialising dictionary ` `ini_dict ``=` `[{``'a'``:``1``}, {``'b'``:``2``}, {``'c'``:``3``}] ` ` `  `# printing initial dictionary ` `print` `(``"initial dictionary"``, ``str``(ini_dict)) ` ` `  `# code to flatten lit of dictionary ` `res ``=` `reduce``(``lambda` `d, src: d.update(src) ``or` `d, ini_dict, {}) ` `     `  `# printing result ` `print` `(``"result"``, ``str``(res)) `

Output:

```initial dictionary [{'a': 1}, {'b': 2}, {'c': 3}]
result {'a': 1, 'c': 3, 'b': 2}
```

Method #4: Using `collections.ChainMap`

 `# Python code to demonstrate ` `# to flatten list of  ` `# dictionaries ` ` `  `from` `collections ``import` `ChainMap ` ` `  `# Initialising dictionary ` `ini_dict ``=` `[{``'a'``:``1``}, {``'b'``:``2``}, {``'c'``:``3``}] ` ` `  `# printing initial dictionary ` `print` `(``"initial dictionary"``, ``str``(ini_dict)) ` ` `  `# code to flatten lit of dictionary ` `res ``=` `ChainMap(``*``ini_dict) ` `     `  `# printing result ` `print` `(``"result"``, ``str``(res)) `

Output:

```initial dictionary [{'a': 1}, {'b': 2}, {'c': 3}]
result ChainMap({'a': 1}, {'b': 2}, {'c': 3})
```

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