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Python | Find smallest element greater than K
• Last Updated : 26 Nov, 2018

Given a list, write a Python program to find the smallest number which is greater than a specific element K.

Let’s see all the approaches to solve this problem, from naive to one-liners so that they can be used in programming whenever required.

Method #1 : Naive Method
Using loop we keep on re-initializing the named variable if we find the element smaller than the previous value than the named variable and greater than K.

 `# Python3 code to demonstrate ``# smallest number greater than K``# using naive method `` ` `# Initializing list ``test_list ``=` `[``1``, ``4``, ``7``, ``5``, ``10``]`` ` `# Initializing k``k ``=` `6`` ` `# Printing original list ``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# Using naive method ``# to find smallest number``# greater than K``min_val ``=` `10000000``for` `i ``in` `test_list :``    ``if` `min_val > i ``and` `i > k :``        ``min_val ``=` `i`` ` `# Printing result ``print` `(``"The minimum value greater than 6 is : "` `+` `str``(min_val))`

Output :

```The original list is : [1, 4, 7, 5, 10]
The minimum value greater than 6 is : 7
```

Method #2 : Using `min()` + generator expression
`min()` returns the minimum number in a sequence and coupling it with a generator expression can perform this task in much concise way and hence more useful when required to save time.

 `# Python3 code to demonstrate ``# smallest number greater than K``# using min() + generator expression`` ` `# Initializing list ``test_list ``=` `[``1``, ``4``, ``7``, ``5``, ``10``]`` ` `# Initializing k``k ``=` `6`` ` `# Printing original list ``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# Using min() + generator expression``# to find smallest number``# greater than K``min_val ``=` `min``(i ``for` `i ``in` `test_list ``if` `i > k)`` ` `# Printing result ``print` `(``"The minimum value greater than 6 is : "` `+` `str``(min_val))`

Output :

```The original list is : [1, 4, 7, 5, 10]
The minimum value greater than 6 is : 7
```

Method #3 :` min() + filter()`
Similar approach to method above, just to filter the numbers in list greater than k, `filter() `instead of generator expression is used in this approach. Works in a similar way as above.

 `# Python3 code to demonstrate ``# smallest number greater than K``# using min() + filter()`` ` `# Initializing list ``test_list ``=` `[``1``, ``4``, ``7``, ``5``, ``10``]`` ` `# Initializing k``k ``=` `6`` ` `# Printing original list ``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# Using min() + filter()``# to find smallest number``# greater than K``min_val ``=` `min``(``filter``(``lambda` `i: i > k, test_list))`` ` `# Printing result ``print` `(``"The minimum value greater than 6 is : "` `+` `str``(min_val))`

Output :

```The original list is : [1, 4, 7, 5, 10]
The minimum value greater than 6 is : 7
```

Method #4 : Using `sort() + bisect_right()`
`bisect_right()` coupled with `sort()` performs the task of binary search for us, and hence is a good option to achieve the solution to this problem. `bisect_right() `because it returns strictly greater number, not the number itself if it is present in the list.

 `# Python3 code to demonstrate ``# smallest number greater than K``# using sort() + bisect_right()``from` `bisect ``import` `bisect_right`` ` `# Initializing list ``test_list ``=` `[``1``, ``4``, ``7``, ``5``, ``10``]`` ` `# Initializing k``k ``=` `6`` ` `# Printing original list ``print` `(``"The original list is : "` `+` `str``(test_list))`` ` `# Using sort() + bisect_right()``# to find smallest number``# greater than K``test_list.sort()``min_val ``=` `test_list[bisect_right(test_list, k)]`` ` `# Printing result ``print` `(``"The minimum value greater than 6 is : "` `+` `str``(min_val))`

Output :

```The original list is : [1, 4, 7, 5, 10]
The minimum value greater than 6 is : 7
```

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