Sometimes, while working with data, we can have a problem in which we have records and we require to find the lowest K scores from it. This kind of application is popular in web development domain. Let’s discuss certain ways in which this problem can be solved.
Method #1 : Using sorted() + lambda
The combination of above functionality can be used to perform this particular task. In this, we just employ sorted function, and print the lowest K elements using list slicing.
# Python3 code to demonstrate working of # Minimum K records # Using sorted() + lambda # Initializing list test_list = [('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)] # Initializing K K = 2 # printing original list print("The original list is : " + str(test_list)) # Minimum K records # Using sorted() + lambda res = sorted(test_list, key = lambda x: x[1])[:K] # printing result print("The lowest K records are : " + str(res)) |
The original list is : [('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)]
The lowest K records are : [('Akash', 2), ('Akshat', 4)]
Method #2 : Using sorted() + itemgetter()
The combination of above functions can also be used to perform this particular task. In this, the task performed by lambda function is performed by itemgetter() is used to get the index in tuple which has to be included in calculations.
# Python3 code to demonstrate working of # Minimum K records # Using sorted() + itemgetter() from operator import itemgetter # Initializing list test_list = [('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)] # Initializing K K = 2 # printing original list print("The original list is : " + str(test_list)) # Minimum K records # Using sorted() + itemgetter() res = sorted(test_list, key = itemgetter(1))[:K] # printing result print("The lowest K records are : " + str(res)) |
The original list is : [('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)]
The lowest K records are : [('Akash', 2), ('Akshat', 4)]
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