Python – Find Kth Even Element
Given a List, extract Kth occurrence of Even Element.
Input : test_list = [4, 6, 2, 3, 8, 9, 10, 11], K = 3
Output : 8
Explanation : K = 3, i.e 0 based index, 4, 6, 2 and 4th is 8.Input : test_list = [4, 6, 2, 3, 8, 9, 10, 11], K = 2
Output : 2
Explanation : K = 2, i.e 0 based index, 4, 6, and 3rd is 2.
Method #1 : Using list comprehension
In this, we extract list of even elements using % operator and use list index access to get Kth even element.
Python3
# Python3 code to demonstrate working of # Kth Even Element# Using list comprehension # initializing listtest_list = [4, 6, 2, 3, 8, 9, 10, 11] # printing original listprint("The original list is : " + str(test_list)) # initializing K K = 4 # list comprehension to perform iteration and % 2 check res = [ele for ele in test_list if ele % 2 == 0][K] # printing result print("The Kth Even Number : " + str(res)) |
Output
The original list is : [4, 6, 2, 3, 8, 9, 10, 11] The Kth Even Number : 10
Method #2 : Using filter() + lambda
In this, task of finding even elements is done using filter() + lambda function.
Python3
# Python3 code to demonstrate working of # Kth Even Element# Using filter() + lambda # initializing listtest_list = [4, 6, 2, 3, 8, 9, 10, 11] # printing original listprint("The original list is : " + str(test_list)) # initializing K K = 4 # list comprehension to perform iteration and % 2 check res = list(filter(lambda ele : ele % 2 == 0, test_list))[K] # printing result print("The Kth Even Number : " + str(res)) |
Output
The original list is : [4, 6, 2, 3, 8, 9, 10, 11] The Kth Even Number : 10
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