Python – Find first element by second in tuple List
Sometimes, while working with Python records, we can have a problem in which we need to find the first element of tuple from the given second element. This kind of problem can occur in domains such as web development. Let’s discuss certain ways in which this task can be performed.
Input : test_list = [(4, 5), (5, 6), (1, 3), (6, 6)] K = 6 Output : [5, 6] Input : test_list = [(4, 5), (5, 7), (1, 3), (6, 8)] K = 6 Output : []
Method #1 : Using list comprehension This is one of the ways in which this task can be performed. In this, we iterate for each tuple, and if we find key matching to value, we store in result list.
Python3
# Python3 code to demonstrate working of# Find first element by second in tuple List# Using list comprehension# initializing listtest_list = [(4, 5), (5, 6), (1, 3), (6, 9)]# printing original listprint("The original list is : " + str(test_list))# initializing KK = 6# Find first element by second in tuple List# Using list comprehensionres = [x for (x, y) in test_list if y == K]# printing resultprint("The key from value : " + str(res)) |
The original list is : [(4, 5), (5, 6), (1, 3), (6, 9)] The key from value : [5]
Method #2 : Using next() + generator expression This is yet another way in which this task can be solved. In here, the next() is used to get the successive elements and generator expression is used to check for the logic.
Python3
# Python3 code to demonstrate working of# Find first element by second in tuple List# Using next() + generator expression# initializing listtest_list = [(4, 5), (5, 6), (1, 3), (6, 9)]# printing original listprint("The original list is : " + str(test_list))# initializing KK = 6# Find first element by second in tuple List# Using next() + generator expressionres = next((x for x, y in test_list if y == K), None)# printing resultprint("The key from value : " + str(res)) |
The original list is : [(4, 5), (5, 6), (1, 3), (6, 9)] The key from value : 5
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