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Python | Find Dissimilar Elements in Tuples
  • Last Updated : 11 Nov, 2019

Sometimes, while working with tuples, we can have a problem in which we need dissimilar features of two records. This type of application can come in Data Science domain. Let’s discuss certain ways in which this problem can be solved.

Method #1 : Using set() + "^" operator

This task can be performed using symmetric difference functionality offered by XOR operator over sets. The conversion to set is done by set().

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# Python3 code to demonstrate working of
# Dissimilar elements in tuples
# Using set() + "^" operator
  
# initialize tuples
test_tup1 = (3, 4, 5, 6)
test_tup2 = (5, 7, 4, 10)
  
# printing original tuples
print("The original tuple 1 : " + str(test_tup1))
print("The original tuple 2 : " + str(test_tup2))
  
# Dissimilar elements in tuples
# Using set() + "^" operator
res = tuple(set(test_tup1) ^ set(test_tup2))
  
# printing result
print("The Dissimilar elements from tuples are : " + str(res))

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Output :

The original tuple 1 : (3, 4, 5, 6)
The original tuple 2 : (5, 7, 4, 10)
The Dissimilar elements from tuples are : (3, 6, 7, 10)

 



Method #2 : Using symmetric_difference() + set()

This is method similar to above method, the difference is that instead of XOR operator, we use inbuilt function to perform the task of filtering dissimilar elements.

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# Python3 code to demonstrate working of
# Dissimilar elements in tuples
# Using symmetric_difference() + set()
  
# initialize tuples
test_tup1 = (3, 4, 5, 6)
test_tup2 = (5, 7, 4, 10)
  
# printing original tuples
print("The original tuple 1 : " + str(test_tup1))
print("The original tuple 2 : " + str(test_tup2))
  
# Dissimilar elements in tuples
# Using symmetric_difference() + set()
res = tuple(set(test_tup1).symmetric_difference(set(test_tup2)))
  
# printing result
print("The Dissimilar elements from tuples are : " + str(res))

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Output :

The original tuple 1 : (3, 4, 5, 6)
The original tuple 2 : (5, 7, 4, 10)
The Dissimilar elements from tuples are : (3, 6, 7, 10)

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