Given List of tuples, filter only those with all even elements.
Input : test_list = [(6, 4, 2, 8), (5, 6, 7, 6), (8, 1, 2), (7, )]
Output : [(6, 4, 2, 8)]
Explanation : Only 1 tuple with all even elements.Input : test_list = [(6, 4, 2, 9), (5, 6, 7, 6), (8, 1, 2), (7, )]
Output : []
Explanation : No tuple with all even elements.
Method #1 : Using loop
In this, we iterate each tuple, and check for all even elements using % operator and if even one element is odd, tuple is flagged and not added in result list.
Python3
# Python3 code to demonstrate working of # Filter Tuples with All Even Elements # Using loop # initializing list test_list = [(6, 4, 2, 8), (5, 6, 7, 6), (8, 0, 2), (7, )] # printing original list print("The original list is : " + str(test_list)) res_list = [] for sub in test_list: res = True # check if all are even for ele in sub: if ele % 2 != 0: res = False break if res: res_list.append(sub) # printing results print("Filtered Tuples : " + str(res_list)) |
The original list is : [(6, 4, 2, 8), (5, 6, 7, 6), (8, 0, 2), (7, )] Filtered Tuples : [(6, 4, 2, 8), (8, 0, 2)]
Method #2 : Using all() + list comprehension
In this, the task of checking for all elements to be even is done using all(), and list comprehension is used for task of filtering post checking.
Python3
# Python3 code to demonstrate working of # Filter Tuples with All Even Elements # Using all() + list comprehension # initializing list test_list = [(6, 4, 2, 8), (5, 6, 7, 6), (8, 0, 2), (7, )] # printing original list print("The original list is : " + str(test_list)) # testing for tuple to be even using all() res = [sub for sub in test_list if all(ele % 2 == 0 for ele in sub)] # printing results print("Filtered Tuples : " + str(res)) |
The original list is : [(6, 4, 2, 8), (5, 6, 7, 6), (8, 0, 2), (7, )] Filtered Tuples : [(6, 4, 2, 8), (8, 0, 2)]
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