Python – Filter Tuples with All Even Elements

Given List of tuples, filter only those with all even elements.

Input : test_list = [(6, 4, 2, 8), (5, 6, 7, 6), (8, 1, 2), (7, )]
Output : [(6, 4, 2, 8)]
Explanation : Only 1 tuple with all even elements.

Input : test_list = [(6, 4, 2, 9), (5, 6, 7, 6), (8, 1, 2), (7, )]
Output : []
Explanation : No tuple with all even elements.

Method #1 : Using loop

In this, we iterate each tuple, and check for all even elements using % operator and if even one element is odd, tuple is flagged and not added in result list.

Python3

# Python3 code to demonstrate working of
# Filter Tuples with All Even Elements
# Using loop

# initializing list
test_list = [(6, 4, 2, 8), (5, 6, 7, 6), (8, 0, 2), (7, )]

# printing original list
print("The original list is : " + str(test_list))

res_list = []
for sub in test_list:
    res = True

    # check if all are even
    for ele in sub:
        if ele % 2 != 0:
            res = False
            break
    if res:
        res_list.append(sub)

# printing results
print("Filtered Tuples : " + str(res_list))

Output

The original list is : [(6, 4, 2, 8), (5, 6, 7, 6), (8, 0, 2), (7, )]
Filtered Tuples : [(6, 4, 2, 8), (8, 0, 2)]

Method #2 : Using all() + list comprehension

In this, the task of checking for all elements to be even is done using all(), and list comprehension is used for task of filtering post checking.

Python3

# Python3 code to demonstrate working of
# Filter Tuples with All Even Elements
# Using all() + list comprehension

# initializing list
test_list = [(6, 4, 2, 8), (5, 6, 7, 6), (8, 0, 2), (7, )]

# printing original list
print("The original list is : " + str(test_list))

# testing for tuple to be even using all()
res = [sub for sub in test_list if all(ele % 2 == 0 for ele in sub)]

# printing results
print("Filtered Tuples : " + str(res))

Output

The original list is : [(6, 4, 2, 8), (5, 6, 7, 6), (8, 0, 2), (7, )]
Filtered Tuples : [(6, 4, 2, 8), (8, 0, 2)]