Given a Matrix, extract rows with elements multiple of K.
Input : test_list = [[5, 10, 15], [4, 8, 12], [100, 15], [5, 10, 23]], K = 4
Output : [[4, 8, 12]]
Explanation : All are multiples of 4.Input : test_list = [[5, 10, 15], [4, 8, 11], [100, 15], [5, 10, 23]], K = 4
Output : []
Explanation : No rows with all multiples of 4.
Method #1 : Using list comprehension + all()
In this, we check for all elements to be multiple using all(), and iteration of rows occur using list comprehension.
Python3
# Python3 code to demonstrate working of # Access element at Kth index in String # Using list comprehension + all() # initializing string list test_list = [[5, 10, 15], [4, 8, 3], [100, 15], [5, 10, 23]] # printing original list print("The original list is : " + str(test_list)) # initializing K K = 5 res = [sub for sub in test_list if all(ele % K == 0 for ele in sub)] # printing result print("Rows with K multiples : " + str(res)) |
The original list is : [[5, 10, 15], [4, 8, 3], [100, 15], [5, 10, 23]]
Rows with K multiples : [[5, 10, 15], [100, 15]]
Method #2 : Using filter() + lambda + all()
In this, we perform task of filtering using filter() and lambda function and task of checking for all elements in rows using all().
Python3
# Python3 code to demonstrate working of # Access element at Kth index in String # Using filter() + lambda + all() # initializing string list test_list = [[5, 10, 15], [4, 8, 3], [100, 15], [5, 10, 23]] # printing original list print("The original list is : " + str(test_list)) # initializing K K = 5 # using all() to check for all elements being multiples of K res = list(filter(lambda sub : all(ele % K == 0 for ele in sub), test_list)) # printing result print("Rows with K multiples : " + str(res)) |
The original list is : [[5, 10, 15], [4, 8, 3], [100, 15], [5, 10, 23]]
Rows with K multiples : [[5, 10, 15], [100, 15]]
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