Python - Extract Strings with Successive Alphabets in Alphabetical Order

Python – Extract Strings with Successive Alphabets in Alphabetical Order

Last Updated : 01 Oct, 2020

Given a string list, extract list which has any succession of characters as they occur in alphabetical order.

Input : test_list = [‘gfg’, ‘ij’, ‘best’, ‘for’, ‘geeks’]
Output : [‘ij’, ‘gfg’, ‘best’]
Explanation : i-j, f-g, s-t are consecutive pairs.
Input : test_list = [‘gf1g’, ‘in’, ‘besht’, ‘for’, ‘geeks’]
Output : []
Explanation : No consecutive pairs.

Method #1 : Using ord() + loop

In this, we check for each string if it contains and character with is the alphabetic successor to its preceding character, ASCII conversion is done using ord().

Python3

# Python3 code to demonstrate working of 
# Extract Strings with successive Alphabets
# Using ord() + loop
  
# initializing string list
test_list = ['gfg', 'is', 'best', 'for', 'geeks']
  
# printing original list
print("The original list is : " + str(test_list))
  
res = []
for sub in test_list:
      
    # iterating for string 
    for idx in range(len(sub) - 1):
          
        # checking for alphabetic consecution
        if ord(sub[idx]) == ord(sub[idx + 1]) - 1:
            res.append(sub)
            break
      
# printing result 
print("Strings with alphabetic consecution : " + str(res))

Output

The original list is : ['gfg', 'is', 'best', 'for', 'geeks']
Strings with alphabetic consecution : ['gfg', 'best']

Method #2 : Using any() + filter() + lambda

In this, we check for any succession using any(), and task of filtering is done using filter() and lambda function.

Python3

# Python3 code to demonstrate working of
# Extract Strings with successive Alphabets
# Using any() + filter() + lambda
  
# initializing string list
test_list = ['gfg', 'is', 'best', 'for', 'geeks']
  
# printing original list
print("The original list is : " + str(test_list))
  
# filtering using filter, and checking for any substring using any()
res = list(filter(lambda sub: any(ord(sub[idx]) == ord(
    sub[idx + 1]) - 1 for idx in range(len(sub) - 1)), test_list))
  
# printing result
print("Strings with alphabetic consecution : " + str(res))

Output

The original list is : ['gfg', 'is', 'best', 'for', 'geeks']
Strings with alphabetic consecution : ['gfg', 'best']

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