Python | Extract specific keys from dictionary
We have a lot of variations and applications of dictionary container in Python and sometimes, we wish to perform a filter of keys in dictionary, i.e extracting just the keys which are present in particular container. Let’s discuss certain ways in which this can be performed. Method #1 : Using dictionary comprehension + items() This problem can be performed by reconstruction using the keys extracted through items function that wish to be filtered and dictionary function makes the desired dictionary.
Python3
# Python3 code to demonstrate# Extracting specific keys from dictionary# Using dictionary comprehension + items()# initializing dictionarytest_dict = {'nikhil' : 1, "akash" : 2, 'akshat' : 3, 'manjeet' : 4}# printing original listprint("The original dictionary : " + str(test_dict))# Using dictionary comprehension + items()# Extracting specific keys from dictionaryres = {key: test_dict[key] for key in test_dict.keys() & {'akshat', 'nikhil'}}# print resultprint("The filtered dictionary is : " + str(res)) |
Output :
The original dictionary : {'manjeet': 4, 'akshat': 3, 'akash': 2, 'nikhil': 1}
The filtered dictionary is : {'akshat': 3, 'nikhil': 1}Method #2 : Using dict() The dict function can be used to perform this task by converting the logic performed using list comprehension into a dictionary.
Python3
# Python3 code to demonstrate# Extracting specific keys from dictionary# Using dict()# initializing dictionarytest_dict = {'nikhil' : 1, "akash" : 2, 'akshat' : 3, 'manjeet' : 4}# printing original listprint("The original dictionary : " + str(test_dict))# Using dict()# Extracting specific keys from dictionaryres = dict((k, test_dict[k]) for k in ['nikhil', 'akshat'] if k in test_dict)# print resultprint("The filtered dictionary is : " + str(res)) |
C++
#include <iostream>using namespace std;int main() { cout<<"GFG!"; return 0;} |
Output :
The original dictionary : {'manjeet': 4, 'akshat': 3, 'akash': 2, 'nikhil': 1}
The filtered dictionary is : {'akshat': 3, 'nikhil': 1}
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