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Python – Extract Percentages from String

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Given a String, extract all the numbers that are percentages.

Input : test_str = ‘geeksforgeeks 20% is 100% way to get 200% success’ Output : [‘20%’, ‘100%’, ‘200%’] Explanation : 20%, 100% and 200% are percentages present. Input : test_str = ‘geeksforgeeks is way to get success’ Output : [] Explanation : No percentages present.

Method #1 : Using findall() + regex

In this, we employ appropriate regex having “%” symbol in suffix and use findall() to get all occurrences of such numbers from String.

Python3




# Python3 code to demonstrate working of
# Extract Percentages from String
# Using regex + findall()
import re
 
# initializing strings
test_str = 'geeksforgeeks is 100 % way to get 200 % success'
 
# printing original string
print("The original string is : " + str(test_str))
 
# getting required result from string
res = re.findall('\d*%', test_str)
 
# printing result
print("The percentages : " + str(res))


Output

The original string is : geeksforgeeks is 100% way to get 200% success
The percentages : ['100%', '200%']

Time Complexity: O(n)
Auxiliary Space: O(n)

Method #2 : Using re.sub() + split()

In this, we perform split of all words, and then from words that have %,  we remove all non-numeric strings. This can be buggy in cases, we have different ordering of % and numbers in string.

Python3




# Python3 code to demonstrate working of
# Extract Percentages from String
# Using re.sub() + split()
import re
 
# initializing strings
test_str = 'geeksforgeeks is 100 % way to get 200 % success'
 
# printing original string
print("The original string is : " + str(test_str))
 
# extracting words
temp = test_str.split()
 
# using
res = []
for sub in temp:
    if '%' in sub:
         
        # replace empty string to all non-number chars
        res.append(re.sub(r'[^\d, %]', '', sub))
 
 
# printing result
print("The percentages : " + str(res))


Output

The original string is : geeksforgeeks is 100% way to get 200% success
The percentages : ['100%', '200%']

Time complexity: O(n), where n is the length of the test_list. The re.sub() + split() takes O(n) time
Auxiliary Space: O(n), extra space of size n is required



Last Updated : 14 Mar, 2023
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