# Python – Extract Paired Rows

• Last Updated : 08 Dec, 2020

Given a Matrix, the task is to write a Python program to extract all the rows which have paired elements. i.e elements have a frequency of mod 2.

Input : test_list = [[10, 2, 3, 2, 3], [5, 5, 4, 7, 7, 4], [1, 2], [1, 1, 2, 2]]
Output : [[5, 5, 4, 7, 7, 4], [1, 1, 2, 2]]
Explanation : All rows have pair elements, i.e have even occurrence.

Input : test_list = [[10, 2, 3, 2, 3], [5, 5, 4, 7, 4], [1, 2], [1, 1, 2, 2]]
Output : [[1, 1, 2, 2]]
Explanation : All rows have pair elements, i.e have even occurrence.

Method #1 : Using all() + list comprehension + count()

In this, we check for the count of each element using count(), and all() is used to test for all elements’ frequency is divisible by 2.

## Python3

 `# Python3 code to demonstrate working of``# Extract Paired Rows``# Using all() + list comprehension + count()`` ` `# initializing list``test_list ``=` `[[``10``, ``2``, ``3``, ``2``, ``3``], [``5``, ``5``, ``4``, ``7``, ``7``, ``4``],``             ``[``1``, ``2``], [``1``, ``1``, ``2``, ``2``]]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# count() checks for frequency to be mod 2``res ``=` `[row ``for` `row ``in` `test_list ``if` `all``(``  ``row.count(ele) ``%` `2` `=``=` `0` `for` `ele ``in` `row)]`` ` `# printing result``print``(``"Extracted rows : "` `+` `str``(res))`

Output:

The original list is : [[10, 2, 3, 2, 3], [5, 5, 4, 7, 7, 4], [1, 2], [1, 1, 2, 2]]
Extracted rows : [[5, 5, 4, 7, 7, 4], [1, 1, 2, 2]]

Method #2 : Using filter() + lambda + count() + all()

In this, we perform the task of filtering using filter() and lambda function instead of list comprehension. The count() and all() are used to check for the frequency of all the elements in rows.

## Python3

 `# Python3 code to demonstrate working of``# Extract Paired Rows``# Using filter() + lambda + count() + all()`` ` `# initializing list``test_list ``=` `[[``10``, ``2``, ``3``, ``2``, ``3``], [``5``, ``5``, ``4``, ``7``, ``7``, ``4``],``             ``[``1``, ``2``], [``1``, ``1``, ``2``, ``2``]]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# count() checks for frequency to be mod 2``# filter() and lambda used to perform filtering``res ``=` `list``(``filter``(``lambda` `row: ``all``(``  ``row.count(ele) ``%` `2` `=``=` `0` `for` `ele ``in` `row), test_list))`` ` `# printing result``print``(``"Extracted rows : "` `+` `str``(res))`

Output:

The original list is : [[10, 2, 3, 2, 3], [5, 5, 4, 7, 7, 4], [1, 2], [1, 1, 2, 2]]
Extracted rows : [[5, 5, 4, 7, 7, 4], [1, 1, 2, 2]]

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