# Python – Extract Kth element of every Nth tuple in List

Given list of tuples, extract Kth column element of every Nth tuple.

Input :test_list = [(4, 5, 3), (3, 4, 7), (4, 3, 2), (4, 7, 8), (6, 4, 7), (2, 5, 7), (1, 9, 10), (3, 5, 7)], K = 2, N = 3
Output : [3, 8, 10]
Explanation : From 0th, 3rd, and 6th tuple, 2nd elements are 3, 8, 10.

Input :test_list = [(4, 5, 3), (3, 4, 7), (4, 3, 2), (4, 7, 8), (6, 4, 7), (2, 5, 7), (1, 9, 10), (3, 5, 7)], K = 0, N = 3
Output : [4, 4, 1]
Explanation : From 0th, 3rd, and 6th tuple, 0th elements are 4, 4, 1.

Method #1 : Using loop

In this, we iterate by skipping N values using 3rd parameter of range(), and append every Kth value in list using loop.

## Python3

 `# Python3 code to demonstrate working of  ` `# Extract Kth element of every Nth tuple in List ` `# Using loop ` ` `  `# initializing list ` `test_list ``=` `[(``4``, ``5``, ``3``), (``3``, ``4``, ``7``), (``4``, ``3``, ``2``), (``4``, ``7``, ``8``), ` `             ``(``6``, ``4``, ``7``), (``2``, ``5``, ``7``), (``1``, ``9``, ``10``), (``3``, ``5``, ``7``)] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# initializing K ` `K ``=` `1` ` `  `# initializing N  ` `N ``=` `3` ` `  `res ``=` `[] ` `for` `idx ``in` `range``(``0``, ``len``(test_list), N): ` `     `  `    ``# extract Kth element ` `    ``res.append(test_list[idx][K]) ` ` `  `# printing result  ` `print``(``"The extracted elements : "` `+` `str``(res)) `

Output

```The original list is : [(4, 5, 3), (3, 4, 7), (4, 3, 2), (4, 7, 8), (6, 4, 7), (2, 5, 7), (1, 9, 10), (3, 5, 7)]
The extracted elements : [5, 7, 9]
```

Method #2 : Using list comprehension

In this, we perform task of extracted elements using one-liner using list comprehension, using same method as above.

## Python3

 `# Python3 code to demonstrate working of  ` `# Extract Kth element of every Nth tuple in List ` `# Using list comprehension ` ` `  `# initializing list ` `test_list ``=` `[(``4``, ``5``, ``3``), (``3``, ``4``, ``7``), (``4``, ``3``, ``2``), (``4``, ``7``, ``8``), ` `             ``(``6``, ``4``, ``7``), (``2``, ``5``, ``7``), (``1``, ``9``, ``10``), (``3``, ``5``, ``7``)] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# initializing K ` `K ``=` `1` ` `  `# initializing N  ` `N ``=` `3` ` `  `# Skipping N using 3rd param of range() ` `res ``=` `[test_list[idx][K] ``for` `idx ``in` `range``(``0``, ``len``(test_list), N)] ` ` `  `# printing result  ` `print``(``"The extracted elements : "` `+` `str``(res))`

Output

```The original list is : [(4, 5, 3), (3, 4, 7), (4, 3, 2), (4, 7, 8), (6, 4, 7), (2, 5, 7), (1, 9, 10), (3, 5, 7)]
The extracted elements : [5, 7, 9]
```

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