# Python – Extract ith column values from jth column values

Sometimes, while working with Python Matrix, we can have a problem in which we need to extract ith column values from comparing values from jth column. This kind of problem can occur in domains such as school programming or web development. Let’s discuss certain ways in which this task can be performed.

Input : test_list = [[4, 5, 6], [2, 5, 7], [9, 8, 2], [10, 2, 6]], search_list = [4, 9], search_idx = 0, ext_idx = 2
Output : [6, 2]

Input : test_list = [[4, 5, 6], [2, 5, 7], [9, 8, 2], [10, 2, 6]], search_list = [2, 6], search_idx = 2, ext_idx = 0
Output : [4, 9, 10]

Method #1 : Using loop
This is brute way to solve this problem. In this, we loop through each row and compare the jth column with list elements, if present, extract the ith element.

 `# Python3 code to demonstrate working of  ` `# Extract ith column values from jth column values ` `# Using loop ` ` `  `# initializing list ` `test_list ``=` `[[``4``, ``5``, ``6``], [``2``, ``5``, ``7``], [``9``, ``8``, ``2``], [``10``, ``2``, ``6``]] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# initializing list  ` `search_list ``=` `[``5``, ``2``] ` ` `  `# initializing search index  ` `search_idx ``=` `1` ` `  `# initializing extract index ` `ext_idx ``=` `2` ` `  `# Extract ith column values from jth column values ` `# Using loop ` `res ``=` `[] ` `for` `sub ``in` `test_list: ` `    ``if` `sub[search_idx] ``in` `search_list: ` `        ``res.append(sub[ext_idx]) ` `   `  `# printing result  ` `print``(``"The extracted elements : "` `+` `str``(res))  `

Output :

```The original list is : [[4, 5, 6], [2, 5, 7], [9, 8, 2], [10, 2, 6]]
The extracted elements : [6, 7, 6]
```

Method #2 : Using `set() + list comprehension`
The combination of above functions can be used to solve this problem. In this, we perform the task of extracting elements in a similar way as above method, just using shorthand. Also, for initial data search reduction, the search list is converted to set(), to remove duplicated.

 `# Python3 code to demonstrate working of  ` `# Extract ith column values from jth column values ` `# Using set() + list comprehension ` ` `  `# initializing list ` `test_list ``=` `[[``4``, ``5``, ``6``], [``2``, ``5``, ``7``], [``9``, ``8``, ``2``], [``10``, ``2``, ``6``]] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# initializing list  ` `search_list ``=` `[``5``, ``2``] ` ` `  `# initializing search index  ` `search_idx ``=` `1` ` `  `# initializing extract index ` `ext_idx ``=` `2` ` `  `# Extract ith column values from jth column values ` `# Using set() + list comprehension ` `temp ``=` `set``(search_list) ` `res ``=` `[sub[ext_idx] ``for` `sub ``in` `test_list ``if` `sub[search_idx] ``in` `search_list] ` `   `  `# printing result  ` `print``(``"The extracted elements : "` `+` `str``(res))  `

Output :

```The original list is : [[4, 5, 6], [2, 5, 7], [9, 8, 2], [10, 2, 6]]
The extracted elements : [6, 7, 6]
```

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