Given a List, extract all elements whose frequency is greater than K.
Input : test_list = [4, 6, 4, 3, 3, 4, 3, 4, 3, 8], K = 3
Output : [4, 3]
Explanation : Both elements occur 4 times.Input : test_list = [4, 6, 4, 3, 3, 4, 3, 4, 6, 6], K = 2
Output : [4, 3, 6]
Explanation : Occur 4, 3, and 3 times respectively.
Method #1 : Using count() + loop
In this, we use count() to get the frequency, and loop is used to iterate for each of elements of List.
Python3
# Python3 code to demonstrate working of # Extract elements with Frequency greater than K # Using count() + loop # initializing list test_list = [4, 6, 4, 3, 3, 4, 3, 7, 8, 8] # printing string print("The original list : " + str(test_list)) # initializing K K = 2 res = [] for i in test_list: # using count() to get count of elements freq = test_list.count(i) # checking if not already entered in results if freq > K and i not in res: res.append(i) # printing results print("The required elements : " + str(res)) |
The original list : [4, 6, 4, 3, 3, 4, 3, 7, 8, 8] The required elements : [4, 3]
Method #2 : Using list comprehension + Counter()
In this, we perform the task of counting using Counter() and the iteration part is done inside list comprehension.
Python3
# Python3 code to demonstrate working of # Extract elements with Frequency greater than K # Using list comprehension + Counter() from collections import Counter # initializing list test_list = [4, 6, 4, 3, 3, 4, 3, 7, 8, 8] # printing string print("The original list : " + str(test_list)) # initializing K K = 2 # using list comprehension to bind result res = [ele for ele, cnt in Counter(test_list).items() if cnt > K] # printing results print("The required elements : " + str(res)) |
The original list : [4, 6, 4, 3, 3, 4, 3, 7, 8, 8] The required elements : [4, 3]
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