# Python | Extend tuples by count of elements in tuple

• Last Updated : 25 Nov, 2022

Sometime, while working with data, we can have a application in which we need to duplicate tuple elements by the amount of element count. This is very unique application but can occur in certain cases. Let’s discuss certain ways in which this task can be performed.
Method #1 : Using nested loops This is the brute force method by which this task can be performed. In this, the outer loop is for iteration to each element in list and inner loop is to add the similar element equating to length of respective tuple by outer loop.

## Python3

 `# Python3 code to demonstrate working of``# Extend tuples by count in list``# using nested loop` `# initialize list of tuple``test_list ``=` `[(``'1'``, ``'4'``, ``'6'``), (``'5'``, ``'8'``), (``'2'``, ``'9'``), (``'1'``, )]` `# printing original tuples list``print``(``"The original list : "` `+` `str``(test_list))` `# Extend tuples by count in list``# using nested loop``res ``=` `[]``for` `sub ``in` `range``(``len``(test_list)):``    ``for` `ele ``in` `range``(``len``(test_list[sub])):``        ``res.append(test_list[sub])` `# printing result``print``(``"The modified and extended list is : "` `+` `str``(res))`

Output

```The original list : [('1', '4', '6'), ('5', '8'), ('2', '9'), ('1',)]
The modified and extended list is : [('1', '4', '6'), ('1', '4', '6'), ('1', '4', '6'), ('5', '8'), ('5', '8'), ('2', '9'), ('2', '9'), ('1',)]
```

Method #2 : Using loop + chain() This is yet another way in which this task can be performed. In this, we reduce one loop, inner loop and multiply the tuples into one and flatten using chain(). It may have certain overheads depending upon different cases.

## Python3

 `# Python3 code to demonstrate working of``# Extend tuples by count in list``# using loop + chain()``from` `itertools ``import` `chain` `# initialize list of tuple``test_list ``=` `[(``'1'``, ``'4'``, ``'6'``), (``'5'``, ``'8'``), (``'2'``, ``'9'``), (``'1'``, )]` `# printing original tuples list``print``(``"The original list : "` `+` `str``(test_list))` `# Extend tuples by count in list``# using loop + chain()``res ``=` `[]``for` `sub ``in` `range``(``len``(test_list)):``    ``res.append([test_list[sub]]``*``len``(test_list[sub]))``res1 ``=` `chain(``*``res)``res ``=` `list``(res1)` `# printing result``print``(``"The modified and extended list is : "` `+` `str``(res))`

Output

```The original list : [('1', '4', '6'), ('5', '8'), ('2', '9'), ('1',)]
The modified and extended list is : [('1', '4', '6'), ('1', '4', '6'), ('1', '4', '6'), ('5', '8'), ('5', '8'), ('2', '9'), ('2', '9'), ('1',)]
```

Method #3 : Using * operator and extend() method

## Python3

 `# Python3 code to demonstrate working of``# Extend tuples by count in list` `# initialize list of tuple``test_list ``=` `[(``'1'``, ``'4'``, ``'6'``), (``'5'``, ``'8'``), (``'2'``, ``'9'``), (``'1'``, )]` `# printing original tuples list``print``(``"The original list : "` `+` `str``(test_list))` `# Extend tuples by count in list``# using nested loop``res ``=` `[]``for` `i ``in` `test_list:``    ``a ``=` `[i]``*``len``(i)``    ``res.extend(a)``# printing result``print``(``"The modified and extended list is : "` `+` `str``(res))`

Output

```The original list : [('1', '4', '6'), ('5', '8'), ('2', '9'), ('1',)]
The modified and extended list is : [('1', '4', '6'), ('1', '4', '6'), ('1', '4', '6'), ('5', '8'), ('5', '8'), ('2', '9'), ('2', '9'), ('1',)]
```

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