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Python | Exponentiation by K in list
  • Last Updated : 29 Dec, 2019

While working with the python lists, we can come over a situation in which we require to exponent constant to each element in the list. We possibly need to iterate and exponent constant to each element but that would increase the line of code. Let’s discuss certain shorthands to perform this task.

Method #1 : Using List Comprehension
List comprehension is just the short way to perform the task we perform using the naive method. This is mainly useful to save time and also is best among others when it comes to readability of the code.




# Python3 code to demonstrate 
# Exponentiation by K in list
# using list comprehension
  
# initializing list 
test_list = [4, 5, 6, 3, 9]
  
# printing original list
print ("The original list is : " + str(test_list))
  
# initializing K
K = 4
  
# using list comprehension
# Exponentiation by K in list
res = [x ** K for x in test_list]
  
# printing result 
print ("The list after constant exponentiation : " + str(res))
Output :
The original list is : [4, 5, 6, 3, 9]
The list after constant exponentiation : [256, 625, 1296, 81, 6561]

 

Method #2 : Using map() + operator.pow
This is similar to the above function but uses the operator.pow to exponent each element to other element from the other list of K formed before applying the map function. It powers the similar index elements of list.






# Python3 code to demonstrate 
# Exponentiation by K in list
# using map() + operator.pow
import operator
  
# initializing list 
test_list = [4, 5, 6, 3, 9]
  
# printing original list
print ("The original list is : " + str(test_list))
  
# initializing K list
K_list = [4] * len(test_list)
  
# using map() + operator.pow
# Exponentiation by K in list
res = list(map(operator.pow, test_list, K_list))
  
# printing result 
print ("The list after constant exponentiation : " + str(res))
Output :
The original list is : [4, 5, 6, 3, 9]
The list after constant exponentiation : [256, 625, 1296, 81, 6561]

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