# Python – Elements frequency in Tuple Matrix

• Last Updated : 17 Feb, 2022

Sometimes, while working with Python Tuple Matrix, we can have a problem in which we need to get the frequency of each element in it. This kind of problem can occur in domains such as day-day programming and web development domains. Let’s discuss certain ways in which this problem can be solved.

Input : test_list = [[(4, 5), (3, 2)], [(2, 2)]]
Output : {4: 1, 5: 1, 3: 1, 2: 3}
Input : test_list = [[(4, 5), (3, 2)]]
Output : {4: 1, 5: 1, 3: 1, 2: 1}

Method #1 : Using nested chain() + “*” operator + Counter()
The combination of the above functions can be used to solve this problem. In this, we perform the task of getting frequency using Counter() and nested chain to cater the nestings, and the “*” operator is used to perform unpacking and packing of each element.

## Python3

 `# Python3 code to demonstrate working of``# Elements frequency in Tuple Matrix``# Using nested chain() + "*" operator + Counter()``from` `itertools ``import` `chain``from` `collections ``import` `Counter` `# initializing lists``test_list ``=` `[[(``4``, ``5``), (``3``, ``2``)], [(``2``, ``2``)], [(``1``, ``2``), (``5``, ``5``)]]` `# printing original list``print``("The original ``list` `is` `: " ``+` `str``(test_list))` `# Elements frequency in Tuple Matrix``# Using nested chain() + "*" operator + Counter()``res ``=` `dict``(Counter(chain(``*``chain(``*``test_list))))` `# printing result``print``("Elements frequency : " ``+` `str``(res))`

Output :

```The original list is : [[(4, 5), (3, 2)], [(2, 2)], [(1, 2), (5, 5)]]
Elements frequency : {4: 1, 5: 3, 3: 1, 2: 4, 1: 1}```

Method #2: Using chain.from_iterables() + Counter()
The combination of the above functions can be used to solve this problem. In this, we perform the task of packing, unpacking, and flattening using chain.from_iterables().

## Python3

 `# Python3 code to demonstrate working of``# Elements frequency in Tuple Matrix``# Using chain.from_iterables() + Counter()``from` `itertools ``import` `chain``from` `collections ``import` `Counter` `# initializing lists``test_list ``=` `[[(``4``, ``5``), (``3``, ``2``)], [(``2``, ``2``)], [(``1``, ``2``), (``5``, ``5``)]]` `# printing original list``print``("The original ``list` `is` `: " ``+` `str``(test_list))` `# Elements frequency in Tuple Matrix``# Using chain.from_iterables() + Counter()``res ``=` `dict``(Counter(chain.from_iterable(chain.from_iterable(test_list))))` `# printing result``print``("Elements frequency : " ``+` `str``(res))`

Output :

```The original list is : [[(4, 5), (3, 2)], [(2, 2)], [(1, 2), (5, 5)]]
Elements frequency : {4: 1, 5: 3, 3: 1, 2: 4, 1: 1}```

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