Python – Double each consecutive duplicate
Sometimes, while working with data, we can have a problem in which we need to perform double of element on each consecutive occurrence of a duplicate. This is very specific problem, but solution to this can prove to be very handy. Lets discuss certain ways in which this task can be performed.
Method #1 : Using loop
This is brute force way to perform this task. In this, we iterate each element and when we find duplicate we store in dictionary and perform its double subsequently.
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# Python3 code to demonstrate # Double each consecutive duplicate# using loop # Initializing listtest_list = [1, 2, 4, 2, 4, 1, 2] # printing original listprint("The original list is : " + str(test_list)) # Double each consecutive duplicate# using looptemp = {}res = []for ele in test_list: temp[ele] = temp1 = temp.get(ele, 0) + ele res.append(temp1) # printing result print ("The list after manipulation is : " + str(res)) |
The original list is : [1, 2, 4, 2, 4, 1, 2] The list after manipulation is : [1, 2, 4, 4, 8, 2, 6]
Method #2 : Using defaultdict() + loop
This method performs this task in similar way as above. The only difference is a step is reduced by using defaultdict() as it pre initializes the list.
# Python3 code to demonstrate # Double each consecutive duplicate# using loop + defaultdict()from collections import defaultdict # Initializing listtest_list = [1, 2, 4, 2, 4, 1, 2] # printing original listprint("The original list is : " + str(test_list)) # Double each consecutive duplicate# using loop + defaultdict()temp = defaultdict(int)res = []for ele in test_list: temp[ele] += ele res.append(temp[ele]) # printing result print ("The list after manipulation is : " + str(res)) |
The original list is : [1, 2, 4, 2, 4, 1, 2] The list after manipulation is : [1, 2, 4, 4, 8, 2, 6]
