# Python – Difference of List keeping duplicates

• Last Updated : 06 Mar, 2020

The problem of finding difference between list, i.e removing elements that occur in one list and not in other is discussed before. But the usage of sets ignores duplicates and we sometimes, require to remove the exact elements that occur in lists. Lets discuss certain ways in which this task can be performed.

Method #1 : Using loop
This is brute way in which this task can be performed. In this, we extract the elements in a form in which we remove elements each time and break the loop to remove one element at a time.

 `# Python3 code to demonstrate ``# Difference of List keeping duplicates``# using loop`` ` `# Initializing lists``test_list1 ``=` `[``4``, ``5``, ``7``, ``4``, ``3``]``test_list2 ``=` `[``7``, ``3``, ``4``]`` ` `# printing original lists``print``(``"The original list 1 is : "` `+` `str``(test_list1))``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Difference of List keeping duplicates``# using loop``for` `ele ``in` `test_list2:``    ``for` `sub ``in` `test_list1:``        ``if` `ele ``=``=` `sub:``            ``test_list1.remove(sub)``            ``break`` ` `# printing result ``print` `(``"List after performing difference : "` `+` `str``(test_list1))`

Output :

```The original list 1 is : [4, 5, 7, 4, 3]
The original list 2 is : [7, 3, 4]
List after performing difference : [5, 4]
```

Method #2 : Using `pop() + list comprehension + index()`
This task can also be performed using combination of above functionalities. In this, we just iterate the list using list comprehension and remove element using index() and pop().

 `# Python3 code to demonstrate ``# Difference of List keeping duplicates``# using pop() + list comprehension + index()`` ` `# Initializing lists``test_list1 ``=` `[``4``, ``5``, ``7``, ``4``, ``3``]``test_list2 ``=` `[``7``, ``3``, ``4``]`` ` `# printing original lists``print``(``"The original list 1 is : "` `+` `str``(test_list1))``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Difference of List keeping duplicates``# using pop() + list comprehension + index()``[test_list1.pop(test_list1.index(idx)) ``for` `idx ``in` `test_list2]`` ` `# printing result ``print` `(``"List after performing difference : "` `+` `str``(test_list1))`

Output :

```The original list 1 is : [4, 5, 7, 4, 3]
The original list 2 is : [7, 3, 4]
List after performing difference : [5, 4]
```

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