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# Python – Dictionary items in value range

• Last Updated : 01 Aug, 2020

Given a range of values, extract all the items whose keys lie in range of values.

Input : {‘Gfg’ : 6, ‘is’ : 7, ‘best’ : 9, ‘for’ : 8, ‘geeks’ : 11}, i, j = 9, 12
Output : {‘best’ : 9, ‘geeks’ : 11}
Explanation : Keys within 9 and 11 range extracted.

Input : {‘Gfg’ : 6, ‘is’ : 7, ‘best’ : 9, ‘for’ : 8, ‘geeks’ : 11}, i, j = 14, 18
Output : {}
Explanation : No values in range.

Method #1 : Using loop

This is brute way in which this task can be performed. In this, we run a loop for all the keys with conditional checks for range of values.

## Python3

 `# Python3 code to demonstrate working of ``# Dictionary items in value range``# Using loop`` ` `# initializing dictionary``test_dict ``=` `{``'Gfg'` `: ``6``, ``'is'` `: ``7``, ``'best'` `: ``9``, ``'for'` `: ``8``, ``'geeks'` `: ``11``} `` ` `# printing original dictionary``print``(``"The original dictionary is : "` `+` `str``(test_dict))`` ` `# initializing range ``i, j ``=` `8``, ``12`` ` `# using loop to iterate through all keys``res ``=` `dict``()``for` `key, val ``in` `test_dict.items():``    ``if` `int``(val) >``=` `i ``and` `int``(val) <``=` `j:``        ``res[key] ``=` `val`` ` `# printing result ``print``(``"The extracted dictionary : "` `+` `str``(res)) `
Output
```The original dictionary is : {'Gfg': 6, 'is': 7, 'best': 9, 'for': 8, 'geeks': 11}
The extracted dictionary : {'best': 9, 'for': 8, 'geeks': 11}
```

Method #2 : Using filter() + lambda + dictionary comprehension

The combination of above functions can be used to solve this problem. In this, we perform task of filtering using filter() and lambda is used for conditional checks.

## Python3

 `# Python3 code to demonstrate working of ``# Dictionary items in value range``# Using filter() + lambda + dictionary comprehension `` ` `# initializing dictionary``test_dict ``=` `{``'Gfg'` `: ``6``, ``'is'` `: ``7``, ``'best'` `: ``9``, ``'for'` `: ``8``, ``'geeks'` `: ``11``} `` ` `# printing original dictionary``print``(``"The original dictionary is : "` `+` `str``(test_dict))`` ` `# initializing range ``i, j ``=` `8``, ``12`` ` `# using dictionary comprehension to compile result in one ``res ``=` `{key: val ``for` `key, val ``in` `filter``(``lambda` `sub: ``int``(sub[``1``]) >``=` `i ``and``                                   ``int``(sub[``1``]) <``=` `j, test_dict.items())}`` ` `# printing result ``print``(``"The extracted dictionary : "` `+` `str``(res)) `
Output
```The original dictionary is : {'Gfg': 6, 'is': 7, 'best': 9, 'for': 8, 'geeks': 11}
The extracted dictionary : {'best': 9, 'for': 8, 'geeks': 11}
```

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