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Python – Custom Rows Removal depending on Kth Column
• Last Updated : 06 Mar, 2020

Sometimes, while working with Python Matrix, we can have a problem in which we need to remove elements from Matrix depending on its Kth Column element present in argument list. This can have application in many domains. Lets discuss certain ways in which this task can be performed.

Method #1 : Using loop
This is brute way in which this task can be performed. In this, we iterate rows of matrix and check for Kth column matching value from list and exclude from new list.

 `# Python3 code to demonstrate ``# Custom Rows Removal depending on Kth Column``# using loop`` ` `# Initializing lists``test_list1 ``=` `[[``3``, ``4``, ``5``], [``2``, ``6``, ``8``], [``1``, ``10``, ``2``], [``5``, ``7``, ``9``], [``10``, ``1``, ``2``]]``test_list2 ``=` `[``12``, ``4``, ``6``]`` ` `# printing original lists``print``(``"The original list 1 is : "` `+` `str``(test_list1))``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Initializing K ``K ``=` `1`` ` `# Custom Rows Removal depending on Kth Column``# using loop``res ``=` `[]``for` `ele ``in` `test_list1:``  ``if` `ele[K] ``not` `in` `test_list2:``    ``res.append(ele)``             ` `# printing result ``print` `(``"The matrix after rows removal is : "` `+` `str``(res))`
Output :

The original list 1 is : [[3, 4, 5], [2, 6, 8], [1, 10, 2], [5, 7, 9], [10, 1, 2]]
The original list 2 is : [12, 4, 6]
The matrix after rows removal is : [[1, 10, 2], [5, 7, 9], [10, 1, 2]]

Method #2 : Using list comprehension
This is yet another way in which this task can be performed. In this, we perform similar task in shortened format using list comprehension in one line.

 `# Python3 code to demonstrate ``# Custom Rows Removal depending on Kth Column``# using list comprehension`` ` `# Initializing lists``test_list1 ``=` `[[``3``, ``4``, ``5``], [``2``, ``6``, ``8``], [``1``, ``10``, ``2``], [``5``, ``7``, ``9``], [``10``, ``1``, ``2``]]``test_list2 ``=` `[``12``, ``4``, ``6``]`` ` `# printing original lists``print``(``"The original list 1 is : "` `+` `str``(test_list1))``print``(``"The original list 2 is : "` `+` `str``(test_list2))`` ` `# Initializing K ``K ``=` `1`` ` `# Custom Rows Removal depending on Kth Column``# using list comprehension``res ``=` `[ele ``for` `ele ``in` `test_list1 ``if` `ele[K] ``not` `in` `test_list2]``             ` `# printing result ``print` `(``"The matrix after rows removal is : "` `+` `str``(res))`
Output :

The original list 1 is : [[3, 4, 5], [2, 6, 8], [1, 10, 2], [5, 7, 9], [10, 1, 2]]
The original list 2 is : [12, 4, 6]
The matrix after rows removal is : [[1, 10, 2], [5, 7, 9], [10, 1, 2]]

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