Python - Cumulative Records Product

Python – Cumulative Records Product

Last Updated : 29 Dec, 2019

Sometimes, while working with data in form of records, we can have a problem in which we need to find the product element of all the records received. This is a very common application that can occur in Data Science domain. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using loop + generator expression
This is the most basic method to achieve solution to this task. In this, we iterate over whole nested lists using generator expression and get the product element using explicit product function.

# Python3 code to demonstrate working of 
# Cummulative Records Product 
# using loop + generator expression 
  
# getting Product 
def prod(val) : 
    res = 1 
    for ele in val: 
        res *= ele 
    return res  
  
# initialize list  
test_list = [(2, 4), (6, 7), (5, 1), (6, 10), (8, 7)] 
  
# printing original list  
print("The original list : " + str(test_list)) 
  
# Cummulative Records Product 
# using loop + generator expression 
res = prod(int(j) for i in test_list for j in i) 
  
# printing result 
print("The Cummulative product of list is : " + str(res)) 

Output :

The original list : [(2, 4), (6, 7), (5, 1), (6, 10), (8, 7)]
The Cummulative product of list is : 5644800

Method #2 : Using loop + map() + chain.from_iterable()
The combination of above methods can also be used to perform this task. In this, the extension of finding product is done by combination of map() and from_iterable().

# Python3 code to demonstrate working of 
# Cummulative Records Product 
# using product + map() + chain.from_iterable() 
from itertools import chain 
  
# getting Product 
def prod(val) : 
    res = 1 
    for ele in val: 
        res *= ele 
    return res  
  
# initialize list  
test_list = [(2, 4), (6, 7), (5, 1), (6, 10), (8, 7)] 
  
# printing original list  
print("The original list : " + str(test_list)) 
  
# Cummulative Records Product 
# using product + map() + chain.from_iterable() 
res = prod(map(int, chain.from_iterable(test_list))) 
  
# printing result 
print("The cummulative product of list is : " + str(res)) 

Output :

The original list : [(2, 4), (6, 7), (5, 1), (6, 10), (8, 7)]
The Cummulative product of list is : 5644800

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