Python – Cumulative List Split
Sometimes, while working with String lists, we can have a problem in which we need to perform the task of split and return all the split instances of list in cumulative way. This kind of problem can occur in many domains in which data is involved. Lets discuss certain ways in which this task can be performed.
Method #1 : Using loop
This is brute force way in which this task is performed. In this, we test for the list and append the list when ever we encounter the split character.
Python3
# Python3 code to demonstrate working of# Cumulative List Split# Using loop# initializing listtest_list = ['gfg-is-all-best']# printing original listprint("The original list is : " + str(test_list))# initializing Split charspl_char = "-"# Cumulative List Split# Using loopres = []for sub in test_list: for idx in range(len(sub)): if sub[idx] == spl_char: res.append([ sub[:idx] ]) res.append([ sub ])# printing resultprint("The Cumulative List Splits : " + str(res)) |
Output
The original list is : ['gfg-is-all-best'] The Cumulative List Splits : [['gfg'], ['gfg-is'], ['gfg-is-all'], ['gfg-is-all-best']]
Method #2 : Using accumulate() + join()
This is one-liner approach to this problem. In this, we perform the task of cutting into cumulative using accumulate and join() is used to construct the resultant List of lists.
Python3
# Python3 code to demonstrate working of# Cumulative List Split# Using accumulate() + join()from itertools import accumulate# initializing listtest_list = ['gfg-is-all-best']# printing original listprint("The original list is : " + str(test_list))# initializing Split charspl_char = "-"# Cumulative List Split# Using accumulate() + join()temp = test_list[0].split(spl_char)res = list(accumulate(temp, lambda x, y: spl_char.join([x, y])))# printing resultprint("The Cumulative List Splits : " + str(res)) |
Output
The original list is : ['gfg-is-all-best'] The Cumulative List Splits : ['gfg', 'gfg-is', 'gfg-is-all', 'gfg-is-all-best']
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