Python Counter to find the size of largest subset of anagram words
Given an array of n string containing lowercase letters. Find the size of largest subset of string which are anagram of each others. An anagram of a string is another string that contains same characters, only the order of characters can be different. For example, “abcd” and “dabc” are anagram of each other.
Examples:
Input:
ant magenta magnate tan gnamate
Output: 3
Explanation
Anagram strings(1) - ant, tan
Anagram strings(2) - magenta, magnate,
gnamate
Thus, only second subset have largest
size i.e., 3
Input:
cars bikes arcs steer
Output: 2
We have existing solution for this problem please refer Find the size of largest subset of anagram words link. We can solve this problem quickly in python using Counter() method. Approach is very simple,
- Split input string separated by space into words.
- As we know two strings are anagram to each other if they contain same character set. So to get all those strings together first we will sort each string in given list of strings.
- Now create a dictionary using Counter method having strings as keys and their frequencies as value.
- Check for maximum value of frequencies, that will be the largest sub-set of anagram strings.
# Function to find the size of largest subset # of anagram words from collections import Counter def maxAnagramSize(input): # split input string separated by space input = input.split(" ") # sort each string in given list of strings for i in range(0,len(input)): input[i]=''.join(sorted(input[i])) # now create dictionary using counter method # which will have strings as key and their # frequencies as value freqDict = Counter(input) # get maximum value of frequency print (max(freqDict.values())) # Driver program if __name__ == "__main__": input = 'ant magenta magnate tan gnamate' maxAnagramSize(input) |
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Output:
3
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