Python counter and dictionary intersection example (Make a string using deletion and rearrangement)
Given two strings, find if we can make first string from second by deleting some characters from second and rearranging remaining characters.
Examples:
Input : s1 = ABHISHEKsinGH
: s2 = gfhfBHkooIHnfndSHEKsiAnG
Output : Possible
Input : s1 = Hello
: s2 = dnaKfhelddf
Output : Not Possible
Input : s1 = GeeksforGeeks
: s2 = rteksfoGrdsskGeggehes
Output : Possible
We have existing solution for this problem please refer Make a string from another by deletion and rearrangement of characters link. We will this problem quickly in python. Approach is very simple,
- Convert both string into dictionary using Counter(iterable) method, each dictionary contains characters within string as Key and their frequencies as Value.
- Now take intersection of two dictionaries and compare resultant output with dictionary of first string, if both are equal that means it is possible to convert string otherwise not.
# Python code to find if we can make first string # from second by deleting some characters from # second and rearranging remaining characters. from collections import Counter def makeString(str1,str2): # convert both strings into dictionaries # output will be like str1="aabbcc", # dict1={'a':2,'b':2,'c':2} # str2 = 'abbbcc', dict2={'a':1,'b':3,'c':2} dict1 = Counter(str1) dict2 = Counter(str2) # take intersection of two dictionries # output will be result = {'a':1,'b':2,'c':2} result = dict1 & dict2 # compare resultant dictionary with first # dictionary comparision first compares keys # and then compares their corresponding values return result == dict1 # Driver program if __name__ == "__main__": str1 = 'ABHISHEKsinGH' str2 = 'gfhfBHkooIHnfndSHEKsiAnG' if (makeString(str1,str2)==True): print("Possible") else: print("Not Possible") |
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Output:
Possible
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