# Python | Count of common elements in the lists

Sometimes, while working with Python list we can have a problem in which we have to compare two lists for index similarity and hence can have a task of counting equal index pairs. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using` sum() + zip()`
This task can be performed by passing the `zip()`, which performs task of mapping both list with each other, to the `sum()` which computes the sum according to equal indices.

 `# Python3 code to demonstrate working of ` `# Identical element summation in lists ` `# using sum() + zip() ` ` `  `# initialize lists ` `test_list1 ``=` `[``5``, ``6``, ``10``, ``4``, ``7``, ``1``, ``19``] ` `test_list2 ``=` `[``6``, ``6``, ``10``, ``3``, ``7``, ``10``, ``19``] ` ` `  `# printing original lists ` `print``(``"The original list 1 is : "` `+` `str``(test_list1)) ` `print``(``"The original list 2 is : "` `+` `str``(test_list2)) ` ` `  `# Identical element summation in lists ` `# using sum() + zip() ` `res ``=` `sum``(x ``=``=` `y ``for` `x, y ``in` `zip``(test_list1, test_list2)) ` ` `  `# printing result ` `print``(``"Summation of Identical elements : "` `+` `str``(res)) `

Output :

```The original list 1 is : [5, 6, 10, 4, 7, 1, 19]
The original list 2 is : [6, 6, 10, 3, 7, 10, 19]
Summation of Identical elements : 4
```

Method #2 : Using `sum() + map() + eq`
The task performed in above method using` zip()` can be executed here using the map function which performs similar task. The equality check can be performed by inbuilt eq operator.

 `# Python3 code to demonstrate working of ` `# Identical element summation in lists ` `# using sum() + map() + eq ` `from` `operator ``import` `eq ` ` `  `# initialize lists ` `test_list1 ``=` `[``5``, ``6``, ``10``, ``4``, ``7``, ``1``, ``19``] ` `test_list2 ``=` `[``6``, ``6``, ``10``, ``3``, ``7``, ``10``, ``19``] ` ` `  `# printing original lists ` `print``(``"The original list 1 is : "` `+` `str``(test_list1)) ` `print``(``"The original list 2 is : "` `+` `str``(test_list2)) ` ` `  `# Identical element summation in lists ` `# using sum() + map() + eq ` `res ``=` `sum``(``map``(eq, test_list1, test_list2)) ` ` `  `# printing result ` `print``(``"Summation of Identical elements : "` `+` `str``(res)) `

Output :

```The original list 1 is : [5, 6, 10, 4, 7, 1, 19]
The original list 2 is : [6, 6, 10, 3, 7, 10, 19]
Summation of Identical elements : 4
```

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