# Python | Count occurrences of an element in a list

Given a list in Python and a number x, count number of occurrences of x in the given list.

Examples:

```Input : lst = [15, 6, 7, 10, 12, 20, 10, 28, 10]
x = 10
Output : 3
10 appears three times in given list.

Input : lst = [8, 6, 8, 10, 8, 20, 10, 8, 8]
x = 16
Output : 0
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Method 1 (Simple approach)
We keep a counter that keeps on increasing if the esquired element is found in the list.

 `# Python code to count the number of occurrences ` `def` `countX(lst, x): ` `    ``count ``=` `0` `    ``for` `ele ``in` `lst: ` `        ``if` `(ele ``=``=` `x): ` `            ``count ``=` `count ``+` `1` `    ``return` `count ` ` `  `# Driver Code ` `lst ``=` `[``8``, ``6``, ``8``, ``10``, ``8``, ``20``, ``10``, ``8``, ``8``] ` `x ``=` `8` `print``(``'{} has occurred {} times'``.``format``(x, countX(lst, x))) `

```Output:
8 has occurred 5 times
```

Method 2 (Using count())
The idea is to use list method count() to count number of occurrences.

 `# Python code to count the number of occurrences ` `def` `countX(lst, x): ` `    ``return` `lst.count(x) ` ` `  `# Driver Code ` `lst ``=` `[``8``, ``6``, ``8``, ``10``, ``8``, ``20``, ``10``, ``8``, ``8``] ` `x ``=` `8` `print``(``'{} has occurred {} times'``.``format``(x, countX(lst, x))) `

```Output:
8 has occurred 5 times
```

Method 2 (Using Counter())
Counter method returns a dictionary with occurrences of all elements as a key-value pair, where key is the element and value is the number of times that element has occurred.

 `from` `collections ``import` `Counter ` ` `  `# declaring the list ` `l ``=` `[``1``, ``1``, ``2``, ``2``, ``3``, ``3``, ``4``, ``4``, ``5``, ``5``] ` ` `  `# driver program ` `x ``=` `3` `d ``=` `Counter(l) ` `print``(``'{} has occurred {} times'``.``format``(x, d[x])) `

```Output:
3 has occurred 2 times
```

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