# Python | Count K character between consecutive characters

Sometimes, while working with strings, we can have a problem in which we need to check the count of each character between the consecutive character. This type of problem can have application in day-day and web development domain. Lets discuss certain ways in which this task can be performed.

Method #1 : Using loop
This is brute force way in which this task can be performed. In this, we iterate the list counting the K character between each of characters.

 `# Python3 code to demonstrate working of  ` `# Count K character between consecutive characters ` `# Using loop ` ` `  `# initializing string ` `test_str ``=` `"g...f..g.i..s....b..e....s...t"` ` `  `# printing original string ` `print``(``"The original string is : "` `+` `test_str) ` ` `  `# initializing K  ` `K ``=` `'.'` ` `  `# Count K character between consecutive characters ` `# Using loop ` `count ``=` `0` `res ``=` `[] ` `for` `ele ``in` `test_str: ` `    ``if` `ele ``=``=` `K: ` `        ``count ``+``=` `1` `    ``else``: ` `        ``res.append(count) ` `        ``count ``=` `0` `res ``=` `res[``1``:] ` ` `  `# printing result  ` `print``(``"List of character count : "` `+` `str``(res))  `

Output :

```The original string is : g...f..g.i..s....b..e....s...t
List of character count : [3, 2, 1, 2, 4, 2, 4, 3]
```

Method #2 : Using list comprehension + `findall()`
This is yet another way in which this problem can be solved. In this, we check for occurring K character using findall() and list comprehension is used to iterate about the string.

 `# Python3 code to demonstrate working of  ` `# Count K character between consecutive characters ` `# Using list comprehension + findall() ` `import` `re ` ` `  `# initializing string ` `test_str ``=` `"g---f--g-i--s----b--e----s---t"` ` `  `# printing original string ` `print``(``"The original string is : "` `+` `test_str) ` ` `  `# Count K character between consecutive characters ` `# Using list comprehension + findall() ` `res ``=` `[``len``(ele) ``for` `ele ``in` `re.findall(``'(?<=[a-z])-*(?=[a-z])'``, test_str)] ` ` `  `# printing result  ` `print``(``"List of character count : "` `+` `str``(res))  `

Output :

```The original string is : g---f--g-i--s----b--e----s---t
List of character count : [3, 2, 1, 2, 4, 2, 4, 3]```

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