Sometimes, while working with Records, we can have a problem, that we have keys in one list and values in other. But sometimes, values can be multiple in order, like the scores or marks of particular subject. This type of problem can occur in school programming and development domains. Lets discuss certain ways in which this task can be performed.
Method #1 : Using dictionary comprehension + enumerate() + list slicing
The combination of above functions can be used to solve this problem. In this, we iterate using dictionary comprehension and enumerate and form desired result by extracting records values by slicing.
# Python3 code to demonstrate working of # Convert Uneven Lists into Records # Using dictionary comprehension + enumerate() + list slicing # initializing lists test_list1 = ['Nikhil', 'Akash', 'Akshat'] test_list2 = [5, 6, 7, 8, 2, 3, 12, 2, 10] # printing original lists print("The original list 1 is : " + str(test_list1)) print("The original list 2 is : " + str(test_list2)) # Convert Uneven Lists into Records # Using dictionary comprehension + enumerate() + list slicing temp = len(test_list2) // len(test_list1) res = {key: test_list2[idx :: temp] for idx, key in enumerate(test_list1)} # printing result print("The paired data dictionary : " + str(res)) |
The original list 1 is : [‘Nikhil’, ‘Akash’, ‘Akshat’]
The original list 2 is : [5, 6, 7, 8, 2, 3, 12, 2, 10]
The paired data dictionary : {‘Nikhil’: [5, 8, 12], ‘Akshat’: [7, 3, 10], ‘Akash’: [6, 2, 2]}
Method #2 : Using list comprehension + zip()
This task can also be solved using above functions. In this, we use list comprehension to construct the cumulated score list. In last step we tie both lists together using zip().
# Python3 code to demonstrate working of # Convert Uneven Lists into Records # Using list comprehension + zip() # initializing lists test_list1 = ['Nikhil', 'Akash', 'Akshat'] test_list2 = [5, 6, 7, 8, 2, 3, 12, 2, 10] # printing original lists print("The original list 1 is : " + str(test_list1)) print("The original list 2 is : " + str(test_list2)) # Convert Uneven Lists into Records # Using list comprehension + zip() temp = len(test_list2) // len(test_list1) res = [test_list2[idx :: temp] for idx in range(0, len(test_list1))] res = dict(zip(test_list1, res)) # printing result print("The paired data dictionary : " + str(res)) |
The original list 1 is : [‘Nikhil’, ‘Akash’, ‘Akshat’]
The original list 2 is : [5, 6, 7, 8, 2, 3, 12, 2, 10]
The paired data dictionary : {‘Nikhil’: [5, 8, 12], ‘Akshat’: [7, 3, 10], ‘Akash’: [6, 2, 2]}
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