Given a dictionary with values as tuple list, convert to key mapped list of tuples.
Input : test_dict = {‘Gfg’ : [(5, 6, 7), (6, )], ‘is’ : [(5, 5, 2, 2, 6)], ‘best’ :[(7, )]}
Output : [(‘Gfg’, 5, 6, 7), (‘Gfg’, 6), (‘is’, 5, 5, 2, 2, 6), (‘best’, 7)]
Explanation : Keys grouped with values.Input : test_dict = {‘Gfg’ : [(5, ), (6, )], ‘is’ : [(5, )], ‘best’ :[(7, )]}
Output : [(‘Gfg’, 5), (‘Gfg’, 6), (‘is’, 5), (‘best’, 7)]
Explanation : Keys grouped with values.
Method #1 : Using loop + * operator + items()
This is one of the ways in which this task can be performed. In this we iterate for all the keys using loop and map keys with all values by unpacking all values in tuple using * operator.
Python3
# Python3 code to demonstrate working of # Convert Tuple value list to List of tuples # Using loop + * operator + items() # initializing dictionary test_dict = {'Gfg' : [(5, 6, 7), (1, 3), (6, )], 'is' : [(5, 5, 2, 2, 6)], 'best' :[(7, ), (9, 16)]} # printing original dictionary print("The original dictionary is : " + str(test_dict)) # using items() to extract all the items of # dictionary res = [] for key, val in test_dict.items(): for ele in val: res.append((key, *ele)) # printing result print("The converted tuple list : " + str(res)) |
The original dictionary is : {‘Gfg’: [(5, 6, 7), (1, 3), (6, )], ‘is’: [(5, 5, 2, 2, 6)], ‘best’: [(7, ), (9, 16)]}
The converted tuple list : [(‘Gfg’, 5, 6, 7), (‘Gfg’, 1, 3), (‘Gfg’, 6), (‘is’, 5, 5, 2, 2, 6), (‘best’, 7), (‘best’, 9, 16)]
Method #2 : Using list comprehension + * operator + items()
This is yet another way to solve this problem. Solves in similar way as above method. Only difference being offers one-liner solution using list comprehension.
Python3
# Python3 code to demonstrate working of # Convert Tuple value list to List of tuples # Using list comprehension + * operator + items() # initializing dictionary test_dict = {'Gfg' : [(5, 6, 7), (1, 3), (6, )], 'is' : [(5, 5, 2, 2, 6)], 'best' :[(7, ), (9, 16)]} # printing original dictionary print("The original dictionary is : " + str(test_dict)) # list comprehension encapsulates whole logic # into one line res = [(key, *ele) for key, sub in test_dict.items() for ele in sub] # printing result print("The converted tuple list : " + str(res)) |
The original dictionary is : {‘Gfg’: [(5, 6, 7), (1, 3), (6, )], ‘is’: [(5, 5, 2, 2, 6)], ‘best’: [(7, ), (9, 16)]}
The converted tuple list : [(‘Gfg’, 5, 6, 7), (‘Gfg’, 1, 3), (‘Gfg’, 6), (‘is’, 5, 5, 2, 2, 6), (‘best’, 7), (‘best’, 9, 16)]
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