Given a Tuple Matrix, flatten to tuple list with each tuple representing each column.
Input : test_list = [[(4, 5), (7, 8)], [(10, 13), (18, 17)]]
Output : [(4, 7, 10, 18), (5, 8, 13, 17)]
Explanation : All column number elements contained together.Input : test_list = [[(4, 5)], [(10, 13)]]
Output : [(4, 10), (5, 13)]
Explanation : All column number elements contained together.
Method #1 : Using list comprehension + zip()
In this, we perform task of flattening using list comprehension and zip() is used to perform column pairing to render as tuple pairs.
Python3
# Python3 code to demonstrate working of # Convert Tuple Matrix to Tuple List # Using list comprehension + zip() # initializing list test_list = [[(4, 5), (7, 8)], [(10, 13), (18, 17)], [(0, 4), (10, 1)]] # printing original list print("The original list is : " + str(test_list)) # flattening temp = [ele for sub in test_list for ele in sub] # joining to form column pairs res = list(zip(*temp)) # printing result print("The converted tuple list : " + str(res)) |
The original list is : [[(4, 5), (7, 8)], [(10, 13), (18, 17)], [(0, 4), (10, 1)]] The converted tuple list : [(4, 7, 10, 18, 0, 10), (5, 8, 13, 17, 4, 1)]
Method #2 : Using chain.from_iterable() + zip()
In this, task of flattening is performed using chain.from_iterable() and zip() is used to perform the task of column pairing.
Python3
# Python3 code to demonstrate working of # Convert Tuple Matrix to Tuple List # Using chain.from_iterable() + zip() from itertools import chain # initializing list test_list = [[(4, 5), (7, 8)], [(10, 13), (18, 17)], [(0, 4), (10, 1)]] # printing original list print("The original list is : " + str(test_list)) # flattening using from_iterable res = list(zip(*chain.from_iterable(test_list))) # printing result print("The converted tuple list : " + str(res)) |
The original list is : [[(4, 5), (7, 8)], [(10, 13), (18, 17)], [(0, 4), (10, 1)]] The converted tuple list : [(4, 7, 10, 18, 0, 10), (5, 8, 13, 17, 4, 1)]
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