# Python – Convert Nested Tuple to Custom Key Dictionary

• Last Updated : 10 Jul, 2020

Sometimes, while working with Python records, we can have data that come without proper column names/identifiers, which can just be identified by their index, but we intend to assign them keys and render in form of dictionaries. This kind of problem can have application in domains such as web development. Let’s discuss certain ways in which this task can be performed.

Input : test_tuple = ((1, ‘Gfg’, 2), (3, ‘best’, 4)), keys = [‘key’, ‘value’, ‘id’]
Output : [{‘key’: 1, ‘value’: ‘Gfg’, ‘id’: 2}, {‘key’: 3, ‘value’: ‘best’, ‘id’: 4}]

Input : test_tuple = test_tuple = ((1, ‘Gfg’), (2, 3)), keys = [‘key’, ‘value’]
Output : [{‘key’: 1, ‘value’: ‘Gfg’}, {‘key’: 2, ‘value’: 3}]

Method #1 : Using list comprehension + dictionary comprehension
The combination of above functionalities can be used to solve this problem. In this, we perform the task of assigning keys using dictionary comprehension and iteration of all keys and constructing data using list comprehension.

 `# Python3 code to demonstrate working of ``# Convert Nested Tuple to Custom Key Dictionary``# Using list comprehension + dictionary comprehension`` ` `# initializing tuple``test_tuple ``=` `((``4``, ``'Gfg'``, ``10``), (``3``, ``'is'``, ``8``), (``6``, ``'Best'``, ``10``))`` ` `# printing original tuple``print``(``"The original tuple : "` `+` `str``(test_tuple))`` ` `# Convert Nested Tuple to Custom Key Dictionary``# Using list comprehension + dictionary comprehension``res ``=` `[{``'key'``: sub[``0``], ``'value'``: sub[``1``], ``'id'``: sub[``2``]} ``                               ``for` `sub ``in` `test_tuple]`` ` `# printing result ``print``(``"The converted dictionary : "` `+` `str``(res))`

Output :

The original tuple : ((4, ‘Gfg’, 10), (3, ‘is’, 8), (6, ‘Best’, 10))
The converted dictionary : [{‘key’: 4, ‘value’: ‘Gfg’, ‘id’: 10}, {‘key’: 3, ‘value’: ‘is’, ‘id’: 8}, {‘key’: 6, ‘value’: ‘Best’, ‘id’: 10}]

Method #2 : Using `zip() `+ list comprehension
The combination of above functions can be used to solve this problem. In this, we assign index wise keys using list content and mapping using zip(). In this, flexibility of predefining/scaling keys is provided.

 `# Python3 code to demonstrate working of ``# Convert Nested Tuple to Custom Key Dictionary``# Using zip() + list comprehension`` ` `# initializing tuple``test_tuple ``=` `((``4``, ``'Gfg'``, ``10``), (``3``, ``'is'``, ``8``), (``6``, ``'Best'``, ``10``))`` ` `# printing original tuple``print``(``"The original tuple : "` `+` `str``(test_tuple))`` ` `# initializing Keys ``keys ``=` `[``'key'``, ``'value'``, ``'id'``]`` ` `# Convert Nested Tuple to Custom Key Dictionary``# Using zip() + list comprehension``res ``=` `[{key: val ``for` `key, val ``in` `zip``(keys, sub)}``                          ``for` `sub ``in` `test_tuple]`` ` `# printing result ``print``(``"The converted dictionary : "` `+` `str``(res))`

Output :

The original tuple : ((4, ‘Gfg’, 10), (3, ‘is’, 8), (6, ‘Best’, 10))
The converted dictionary : [{‘key’: 4, ‘value’: ‘Gfg’, ‘id’: 10}, {‘key’: 3, ‘value’: ‘is’, ‘id’: 8}, {‘key’: 6, ‘value’: ‘Best’, ‘id’: 10}]

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