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Python – Convert List to List of dictionaries

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  • Difficulty Level : Medium
  • Last Updated : 05 Jan, 2022

Given list values and keys list, convert these values to key value pairs in form of list of dictionaries.

Input : test_list = [“Gfg”, 3, “is”, 8], key_list = [“name”, “id”]
Output : [{‘name’: ‘Gfg’, ‘id’: 3}, {‘name’: ‘is’, ‘id’: 8}]
Explanation : Values mapped by custom key, “name” -> “Gfg”, “id” -> 3.

Input : test_list = [“Gfg”, 10], key_list = [“name”, “id”]
Output : [{‘name’: ‘Gfg’, ‘id’: 10}]
Explanation : Conversion of lists to list of records by keys mapping.

Method #1 : Using loop + dictionary comprehension

This is one of the ways in which this task can be performed. In this, we perform mapping values using dictionary comprehension. The iteration is performed using loop.

Python3




# Python3 code to demonstrate working of 
# Convert List to List of dictionaries
# Using dictionary comprehension + loop
  
# initializing lists
test_list = ["Gfg", 3, "is", 8, "Best", 10, "for", 18, "Geeks", 33]
  
# printing original list
print("The original list : " + str(test_list))
  
# initializing key list 
key_list = ["name", "number"]
  
# loop to iterate through elements
# using dictionary comprehension
# for dictionary construction
n = len(test_list)
res = []
for idx in range(0, n, 2):
    res.append({key_list[0]: test_list[idx], key_list[1] : test_list[idx + 1]})
  
# printing result 
print("The constructed dictionary list : " + str(res))

Output

The original list : [‘Gfg’, 3, ‘is’, 8, ‘Best’, 10, ‘for’, 18, ‘Geeks’, 33]
The constructed dictionary list : [{‘name’: ‘Gfg’, ‘number’: 3}, {‘name’: ‘is’, ‘number’: 8}, {‘name’: ‘Best’, ‘number’: 10}, {‘name’: ‘for’, ‘number’: 18}, {‘name’: ‘Geeks’, ‘number’: 33}]

Method #2 : Using dictionary comprehension + list comprehension

The combination of above functions is used to solve this problem. In this, we perform a similar task as above method. But difference is that its performed as shorthand.

Python3




# Python3 code to demonstrate working of 
# Convert List to List of dictionaries
# Using zip() + list comprehension
  
# initializing lists
test_list = ["Gfg", 3, "is", 8, "Best", 10, "for", 18, "Geeks", 33]
  
# printing original list
print("The original list : " + str(test_list))
  
# initializing key list 
key_list = ["name", "number"]
  
# using list comprehension to perform as shorthand
n = len(test_list)
res = [{key_list[0]: test_list[idx], key_list[1]: test_list[idx + 1]}
       for idx in range(0, n, 2)]
  
# printing result 
print("The constructed dictionary list : " + str(res))

Output

The original list : [‘Gfg’, 3, ‘is’, 8, ‘Best’, 10, ‘for’, 18, ‘Geeks’, 33]
The constructed dictionary list : [{‘name’: ‘Gfg’, ‘number’: 3}, {‘name’: ‘is’, ‘number’: 8}, {‘name’: ‘Best’, ‘number’: 10}, {‘name’: ‘for’, ‘number’: 18}, {‘name’: ‘Geeks’, ‘number’: 33}]


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