# Python | Convert list of tuples into digits

Given a list of tuples, the task is to convert it into list of all digits which exists in elements of list.

Let’s discuss certain ways in which this task is performed.

Method #1: Using `re`

The most concise and readable way to convert list of tuple into list of all digits which exists in elements of list is by using re.

 `# Python code to convert list of tuples into ` `# list of all digits which exists ` `# in elements of list. ` ` `  `# Importing ` `import` `re ` ` `  `# Input list initialization ` `lst ``=` `[(``11``, ``100``), (``22``, ``200``), (``33``, ``300``), (``44``, ``400``), (``88``, ``800``)] ` ` `  `# Using re ` `temp ``=` `re.sub(r``'[\[\]\(\), ]'``, '', ``str``(lst)) ` ` `  `# Using set ` `Output ``=` `[``int``(i) ``for` `i ``in` `set``(temp)] ` ` `  `# Printing output ` `print``(``"Initial List is :"``, lst) ` `print``(``"Output list is :"``, Output) `

Output:

Initial List is : [(11, 100), (22, 200), (33, 300), (44, 400), (88, 800)]
Output list is : [1, 4, 8, 0, 3, 2]

Method #2: Using `itertools.chain()` and `lambda()`

This is yet another way to perform this particular task using `lambda()`.

 `# Python code to convert list of tuples into ` `# list of all digits which exists ` `# in elements of list. ` ` `  `# Importing ` `from` `itertools ``import` `chain ` ` `  `# Input list initialization ` `lst ``=` `[(``11``, ``100``), (``22``, ``200``), (``33``, ``300``), (``44``, ``400``), (``88``, ``800``)] ` ` `  `# using lambda ` `temp ``=` `map``(``lambda` `x: ``str``(x), chain.from_iterable(lst)) ` ` `  `# Output list initialization ` `Output ``=` `set``() ` ` `  `# Adding element in Output ` `for` `x ``in` `temp: ` `    ``for` `elem ``in` `x: ` `        ``Output.add(elem) ` ` `  `# Printing output ` `print``(``"Initial List is :"``, lst) ` `print``(``"Output list is :"``, Output) `

Output:

Initial List is : [(11, 100), (22, 200), (33, 300), (44, 400), (88, 800)]
Output list is : {‘8’, ‘4’, ‘0’, ‘2’, ‘1’, ‘3’}

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