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Python | Convert list of tuples into digits

  • Last Updated : 15 Mar, 2019

Given a list of tuples, the task is to convert it into list of all digits which exists in elements of list.

Let’s discuss certain ways in which this task is performed.

Method #1: Using re

The most concise and readable way to convert list of tuple into list of all digits which exists in elements of list is by using re.




# Python code to convert list of tuples into
# list of all digits which exists
# in elements of list.
  
# Importing
import re
  
# Input list initialization
lst = [(11, 100), (22, 200), (33, 300), (44, 400), (88, 800)]
  
# Using re
temp = re.sub(r'[\[\]\(\), ]', '', str(lst))
  
# Using set
Output = [int(i) for i in set(temp)]
  
# Printing output
print("Initial List is :", lst)
print("Output list is :", Output)
Output:



Initial List is : [(11, 100), (22, 200), (33, 300), (44, 400), (88, 800)]
Output list is : [1, 4, 8, 0, 3, 2]

 
Method #2: Using itertools.chain() and lambda()

This is yet another way to perform this particular task using lambda().




# Python code to convert list of tuples into
# list of all digits which exists
# in elements of list.
  
# Importing
from itertools import chain
  
# Input list initialization
lst = [(11, 100), (22, 200), (33, 300), (44, 400), (88, 800)]
  
# using lambda
temp = map(lambda x: str(x), chain.from_iterable(lst))
  
# Output list initialization
Output = set()
  
# Adding element in Output
for x in temp:
    for elem in x:
        Output.add(elem)
  
# Printing output
print("Initial List is :", lst)
print("Output list is :", Output)
Output:

Initial List is : [(11, 100), (22, 200), (33, 300), (44, 400), (88, 800)]
Output list is : {‘8’, ‘4’, ‘0’, ‘2’, ‘1’, ‘3’}

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