Given day number, convert to date it refers to.
Input : day_num = “339”, year = “2020”
Output : 12-04-2020
Explanation : 339th Day of 2020 is 4th December.Input : day_num = “4”, year = “2020”
Output : 01-04-2020
Explanation : 4th Day of 2020 is 4th January.
Method #1 : Using datetime.strptime()
In this, we get the year string and day number string, and pass to strptime(), converts to the corresponding required date.
Python3
# Python3 code to demonstrate working of # Convert day number to date in particular year # Using datetime.strptime() from datetime import datetime # initializing day number day_num = "339" # print day number print("The day number : " + str(day_num)) # adjusting day num day_num.rjust(3 + len(day_num), '0') # Initialize year year = "2020" # converting to date res = datetime.strptime(year + "-" + day_num, "%Y-%j").strftime("%m-%d-%Y") # printing result print("Resolved date : " + str(res)) |
The day number : 339 Resolved date : 12-04-2020
Method #2 : Using timedelta()
In this, we initialize the date by 1st of January and then add number of days using timedelta(), resultant gives the date required.
Python3
# Python3 code to demonstrate working of # Convert day number to date in particular year # Using datetime.strptime() from datetime import datetime, date, timedelta # initializing day number day_num = "339" # print day number print("The day number : " + str(day_num)) # adjusting day num day_num.rjust(3 + len(day_num), '0') # Initialize year year = "2020" # Initializing start date strt_date = date(int(year), 1, 1) # converting to date res_date = strt_date + timedelta(days=int(day_num) - 1) res = res_date.strftime("%m-%d-%Y") # printing result print("Resolved date : " + str(res)) |
The day number : 339 Resolved date : 12-04-2020
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