Sometimes, while working with data, we need to create data as all possible pairs of containers. This type of application comes from web development domain. Let’s discuss certain ways in which this task can be performed.
Method #1 : Using list comprehension
This is one-liner way to perform this particular task. In this, we just shorten the task of loop in one line to generate all possible pairs of tuple with list elements.
# Python3 code to demonstrate working of # Construct Cartesian Product Tuple list # using list comprehension # initialize list and tuple test_list = [ 1 , 4 , 6 , 7 ] test_tup = ( 1 , 3 ) # printing original list and tuple print ( "The original list : " + str (test_list)) print ( "The original tuple : " + str (test_tup)) # Construct Cartesian Product Tuple list # using list comprehension res = [(a, b) for a in test_tup for b in test_list] # printing result print ( "The Cartesian Product is : " + str (res)) |
The original list : [1, 4, 6, 7]
The original tuple : (1, 3)
The Cartesian Product is : [(1, 1), (1, 4), (1, 6), (1, 7), (3, 1), (3, 4), (3, 6), (3, 7)]
Method #2 : Using itertools.product()
This task can also be performed using the single function which internally performs the task of returning the required Cartesian Product.
# Python3 code to demonstrate working of # Construct Cartesian Product Tuple list # using itertools.product() from itertools import product # initialize list and tuple test_list = [ 1 , 4 , 6 , 7 ] test_tup = ( 1 , 3 ) # printing original list and tuple print ( "The original list : " + str (test_list)) print ( "The original tuple : " + str (test_tup)) # Construct Cartesian Product Tuple list # using itertools.product() res = list (product(test_tup, test_list)) # printing result print ( "The Cartesian Product is : " + str (res)) |
The original list : [1, 4, 6, 7]
The original tuple : (1, 3)
The Cartesian Product is : [(1, 1), (1, 4), (1, 6), (1, 7), (3, 1), (3, 4), (3, 6), (3, 7)]
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