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# Python – Consecutive Kth column Difference in Tuple List

• Last Updated : 11 Oct, 2020

Sometimes, while working with Python list, we can have a task in which we need to work with tuple list and get the absolute difference of it’s Kth index. This problem has application in web development domain while working with data informations. Let’s discuss certain ways in which this task can be performed.

Examples:

Input : test_list = [(5, 4, 2), (1, 3, 4), (5, 7, 8), (7, 4, 3)], K = 0
Output : [4, 4, 2]
Explanation : 5 – 1 = 4, hence 4.

Input : test_list = [(5, 4, 2), (1, 3, 4), (5, 7, 8), (7, 4, 3)], K = 2
Output : [2, 4, 5]
Explanation : 8 – 3 = 5, hence 5.

Method #1: Using loop

In this, for each tuple we subtract and find absolute difference of Kth column tuples with consecutive tuples in list.

## Python3

 `# Python3 code to demonstrate working of ``# Consecutive Kth column Difference in Tuple List``# Using loop`` ` `# initializing list``test_list ``=` `[(``5``, ``4``, ``2``), (``1``, ``3``, ``4``), (``5``, ``7``, ``8``), (``7``, ``4``, ``3``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `1` ` ` `res ``=` `[]``for` `idx ``in` `range``(``0``, ``len``(test_list) ``-` `1``):`` ` `    ``# getting difference using abs()``    ``res.append(``abs``(test_list[idx][K] ``-` `test_list[idx ``+` `1``][K]))``     ` `# printing result ``print``(``"Resultant tuple list : "` `+` `str``(res))`

Output:

The original list is : [(5, 4, 2), (1, 3, 4), (5, 7, 8), (7, 4, 3)]
Resultant tuple list : [1, 4, 3]

Method #2 : Using zip() + list comprehension

In this, we iterate for all the element in list using list comprehension and compare elements paired using zip().

## Python3

 `# Python3 code to demonstrate working of ``# Consecutive Kth column Difference in Tuple List``# Using zip() + list comprehension`` ` `# initializing list``test_list ``=` `[(``5``, ``4``, ``2``), (``1``, ``3``, ``4``), (``5``, ``7``, ``8``), (``7``, ``4``, ``3``)]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `1` ` ` `# zip used to pair each tuple with subsequent tuple``res ``=` `[``abs``(x[K] ``-` `y[K]) ``for` `x, y ``in` `zip``(test_list, test_list[``1``:])]``     ` `# printing result ``print``(``"Resultant tuple list : "` `+` `str``(res))`

Output:

The original list is : [(5, 4, 2), (1, 3, 4), (5, 7, 8), (7, 4, 3)]
Resultant tuple list : [1, 4, 3]

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